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我想創造什麼樣的，我認爲是一個在線商店相對基本的報告，使用MySQL 45年5月1日使用MySQL來生成與彌補的差距每日銷售報告，通過貨幣
商店可以接收付款分組以多種貨幣。 我已經創建了一些包含數據的示例表，並且試圖生成一個按日期和貨幣分組的簡單表格結果集，以便我可以繪製這些數字。
我想查看每個日期可用的每種貨幣，如果當天沒有以該貨幣進行的銷售，結果爲0。 如果我可以得到這個工作，我想要做同樣的事情，但也按產品ID分組。
在我提供的樣本數據中，只有3種貨幣和2種產品ID，但實際上可以有任何數量的每種。
我可以按日期正確分組，但隨後當我通過貨幣添加分組時，我的查詢不會返回我想要的。
我基於我的作品this article。
我的報表查詢，僅按日期分組：
SELECT calendar.datefield AS date,
IFNULL(SUM(orders.order_value),0) AS total_value
FROM orders
RIGHT JOIN calendar ON (DATE(orders.order_date) = calendar.datefield)
WHERE (calendar.datefield BETWEEN (SELECT MIN(DATE(order_date)) FROM orders) AND (SELECT MAX(DATE(order_date)) FROM orders))
GROUP BY date
現在按日期和貨幣分組：
：SELECT calendar.datefield AS date, orders.currency_id,
IFNULL(SUM(orders.order_value),0) AS total_value
FROM orders
RIGHT JOIN calendar ON (DATE(orders.order_date) = calendar.datefield)
WHERE (calendar.datefield BETWEEN (SELECT MIN(DATE(order_date)) FROM orders) AND (SELECT MAX(DATE(order_date)) FROM orders))
GROUP BY date, orders.currency_id
我得到的結果（按日期和貨幣分組）
+------------+-------------+-------------+
| date | currency_id | total_value |
+------------+-------------+-------------+
| 2009-08-15 | 3 | 81.94 |
| 2009-08-15 | 45 | 25.00 |
| 2009-08-15 | 49 | 122.60 |
| 2009-08-16 | NULL | 0.00 |
| 2009-08-17 | 45 | 25.00 |
| 2009-08-17 | 49 | 122.60 |
| 2009-08-18 | 3 | 81.94 |
| 2009-08-18 | 49 | 245.20 |
+------------+-------------+-------------+
結果I 想要：
+------------+-------------+-------------+
| date | currency_id | total_value |
+------------+-------------+-------------+
| 2009-08-15 | 3 | 81.94 |
| 2009-08-15 | 45 | 25.00 |
| 2009-08-15 | 49 | 122.60 |
| 2009-08-16 | 3 | 0.00 |
| 2009-08-16 | 45 | 0.00 |
| 2009-08-16 | 49 | 0.00 |
| 2009-08-17 | 3 | 0.00 |
| 2009-08-17 | 45 | 25.00 |
| 2009-08-17 | 49 | 122.60 |
| 2009-08-18 | 3 | 81.94 |
| 2009-08-18 | 45 | 0.00 |
| 2009-08-18 | 49 | 245.20 |
+------------+-------------+-------------+
的架構和數據，我用我的測試：
CREATE TABLE orders
(
id INT PRIMARY KEY AUTO_INCREMENT,
order_date DATETIME,
order_id INT,
product_id INT,
currency_id INT,
order_value DECIMAL(9,2),
customer_id INT
);
INSERT INTO orders (order_date, order_id, product_id, currency_id, order_value, customer_id)
VALUES
('2009-08-15 10:20:20', '123', '1', '45', '12.50', '322'),
('2009-08-15 12:30:20', '124', '1', '49', '122.60', '400'),
('2009-08-15 13:41:20', '125', '1', '3', '40.97', '324'),
('2009-08-15 10:20:20', '126', '2', '45', '12.50', '345'),
('2009-08-15 13:41:20', '131', '2', '3', '40.97', '756'),
('2009-08-17 10:20:20', '3234', '1', '45', '12.50', '1322'),
('2009-08-17 10:20:20', '4642', '2', '45', '12.50', '1345'),
('2009-08-17 12:30:20', '23', '2', '49', '122.60', '3142'),
('2009-08-18 12:30:20', '2131', '1', '49', '122.60', '4700'),
('2009-08-18 13:41:20', '4568', '1', '3', '40.97', '3274'),
('2009-08-18 12:30:20', '956', '2', '49', '122.60', '3542'),
('2009-08-18 13:41:20', '443', '2', '3', '40.97', '7556');
CREATE TABLE currency
(
id INT PRIMARY KEY,
name VARCHAR(255)
);
INSERT INTO currency (id, name)
VALUES
(3, 'Euro'),
(45, 'US Dollar'),
(49, 'CA Dollar');
CREATE TABLE calendar (datefield DATE);
DELIMITER |
CREATE PROCEDURE fill_calendar(start_date DATE, end_date DATE)
BEGIN
DECLARE crt_date DATE;
SET crt_date=start_date;
WHILE crt_date < end_date DO
INSERT INTO calendar VALUES(crt_date);
SET crt_date = ADDDATE(crt_date, INTERVAL 1 DAY);
END WHILE;
END |
DELIMITER ;
CALL fill_calendar('2008-01-01', '2011-12-31');