Python計算器代碼

Question

我是相當新的python，並試圖開發一個計算器。我已經創建了它，以便在你按9並退出之前一直詢問你的問題。我做了一個錯誤，而這樣做的，它一直要求我輸入第一個號碼並不斷循環，這

loop = 1 
oper = 0 

while loop == 1:  
    num1 = input("Enter the first number: ") 
    print num1 

    oper = input("+, -, *, /,9: ") 
    print oper 

    num2 = input("Enter the second number: ") 
    print num2 

    if oper == "+": 
     result = int(num1) + int(num2) 
    elif oper == "-": 
     result = int(num1) - int(num2) 
    elif oper == "*": 
     result = int(num1) * int(num2) 
    elif oper == "/": 
     result = int(num1)/int(num2) 
    elif oper == "9": 
     loop = 0 


    print "The result of " + str(num1) + str(oper) + str(num2) + " is " + str(result) 

    input("\nPress 9 to exit.") 

Answer 1

您有相關問題，壓痕和這裏是一個更好的辦法利用休息while循環退出：

loop = 1 
oper = 0 

while loop == 1: 

    x = input("Press 9 to exit otherwise anything to continue:")#much better way 
    if x == "9": 
     break 
    num1 = input("Enter the first number: ") 
    print (num1) 

    oper = input("+, -, *, /: ") 
    print (oper) 

    num2 = input("Enter the second number: ") 
    print (num2) 

    if oper == "+": 
     result = int(num1) + int(num2) 
    elif oper == "-": 
     result = int(num1) - int(num2) 
    elif oper == "*": 
     result = int(num1) * int(num2) 
    elif oper == "/": 
     result = int(num1)/int(num2): 
    else: 
     print("Invalid operator!") #if user inputs something else other than those 


    print ("The result of " + str(num1) + str(oper) + str(num2) + " is " + str(result)) 

Answer 2

這是因爲你做任何事情首先打破。試着改變你的oper包括9：

oper = raw_input("+, -, /, *, or 9 (to exit)":) 

然後包括elif聲明並更改loop 0退出while循環：

elif oper == "9": 
    loop = 0 

而且，處理您的縮進：

loop = 1 

while loop == 1:  

    num1 = input("Enter the first number: ") 
    print num1 

    oper = input("+, -, *, /,9: ") 
    print oper 

    num2 = input("Enter the second number: ") 
    print num2 

    if oper == "+": 
     result = int(num1) + int(num2) 
    elif oper == "-": 
     result = int(num1) - int(num2) 
    elif oper == "*": 
     result = int(num1) * int(num2) 
    elif oper == "/": 
     result = int(num1)/int(num2) 
    elif oper == "9": 
     loop = 0 


print "The result of " + str(num1) + str(oper) + str(num2) + " is " + str(result) 

Answer 3

這個問題似乎是你沒有縮進。 Python關心你縮進多少，因此只有縮進行將被視爲while循環的一部分。這裏只有第一行（num1 = input...）被認爲是while循環的一部分。解決這個問題的最簡單方法是在應該在循環中的每一行之前添加四個空格（以及在if語句中的每行之前另外添加四個空格）。

有關更多幫助，請參閱http://www.diveintopython.net/getting_to_know_python/indenting_code.html。