1
我在電影/電影管理系統中遇到問題。我有表,使用LINQ組織數據庫結果
表電影
+----+------------------+---------------------------+
| Id | Name | Description |
+----+------------------+---------------------------+
| 1 | Kabaddi Kabaddi |Kabaddi Kabaddi is a... |
| 2 | Kabaddi |Kabaddi is a... |
| 3 | Jholay |A man hopes to achieve... |
| 4 | Nai Nabhannu La | |
+----+------------------+---------------------------+
表角色
+----+----------+
| Id | Name |
+----+----------+
| 1 | Actor |
| 2 | Actress |
| 3 | Director |
+----+----------+
表人民
+----+--------------+---------------+-----------+
| Id | FirstName | MiddleName | LastName |
+----+--------------+---------------+-----------+
| 1 | Dayahang | | Rai |
| 2 | Priyanka | | Karki |
| 3 | Nischal | | Basnet |
+----+--------------+---------------+-----------+
表施放
+-----------+-----------+-----------+
| FilmId | PersonId | RoleId |
+-----------+-----------+-----------+
| 1 | 1 | 1 |
| 2 | 1 | 1 |
| 3 | 1 | 1 |
| 2 | 3 | 1 |
| 1 | 3 | 1 |
| 2 | 3 | 3 |
| 1 | 3 | 3 |
| 4 | 2 | 2 |
+-----------+-----------+-----------+
我的目標是獲得與使用單個查詢各自的角色各自鑄件的電影名單。
Kabaddi Kabaddi <FilmName>
Dayahang <CastFirstName>
Actor <RoleName>
Nischal <CastFirstName>
Actor <RoleName>
Director <RoleName>
Jholay <FilmName>
Dayahang <CastFirstName>
Actor <RoleName>
Priyanka <CastFirstName>
Actress <RoleName>
最好的我已經試過是
var result = from cast in entity.Casts
join film in entity.Films on cast.FilmId equals film.Id
join person in entity.People on cast.PersonId equals person.Id
join role in entity.Roles on cast.RoleId equals role.Id
導致
+-------------------+---------------+-----------+
| FilmName | CastFirstName | RoleName |
+-------------------+---------------+-----------+
| Kabaddi Kabaddi | Dayahang | Actor |
| Kabaddi | Dayahang | Actor |
| Jholay | Dayahang | Actor |
| Kabaddi | Nischal | Actor |
| Kabaddi Kabaddi | Nischal | Actor |
| Kabaddi | Nischal | Director |
| Kabaddi Kabaddi | Nischal | Director |
| Nai Nabhannu La | Nischal | Actress |
+-------------------+---------------+-----------+
是否有可能在一個單一的查詢?怎麼樣?
但它是一個單一的查詢... –
不要你已經有你的答案與自己的碼?問題是什麼? – 2016-09-14 05:36:27
但FilmName正在重複。我需要按照「我的目標是獲得電影列表......」之後提到的順序。 – srekcahrai