UIImagePickerController通過iPhone中的彈出窗口模型

Question

您好朋友我想在點擊彈出視圖的圖像按鈕後打開imagepicker視圖。現在重點是沒有彈出窗口完美的工作。但我不知道如何在調制解調器彈出窗口中實現它。我怎麼能夠 ？

Answer 1

//試試這個。

 if ([UIImagePickerController isSourceTypeAvailable:UIImagePickerControllerSourceTypePhotoLibrary]) { 
     imagePickerController_.sourceType = UIImagePickerControllerSourceTypePhotoLibrary; 
       [popover_ presentPopoverFromRect:[sender bounds] inView:sender 
      permittedArrowDirections:UIPopoverArrowDirectionAny animated:YES]; 
     ... 


     } 

這裏發送者是您單擊// UIButton的

Answer 2

對象這可能有助於你

-(IBAction)Click_event 
    { 
    UIImagePickerController *imagePickerController_=[[UIImagePickerController alloc] init]; 
    UIPopoverController *popover_=[[UIPopoverController alloc] 
    initWithContentViewController:imagePickerController_]; 

    if ([UIImagePickerController isSourceTypeAvailable:UIImagePickerControllerSourceTypePhotoLibrary]) { 

     imagePickerController_.sourceType =UIImagePickerControllerSourceTypePhotoLibrary; 
     [popover_ presentPopoverFromRect:CGRectMake(400, 400, 0, 0) inView:self.Mybutton 
     permittedArrowDirections:UIPopoverArrowDirectionAny animated:YES]; 
    } 
    }