我正在嘗試爲即時輸入更改上的關鍵字執行數據庫查詢。現在,我得到一個成功的查詢,並存儲了所有結果,但在GET
上顯示它們,我的ajax
函數返回false。它爲什麼這樣做?AJAX返回false但我不明白爲什麼?
控制檯輸出:
POST http://example.com/functions/ajax.php
response: the data i need to display
接着是
GET http://example.com/functions/ajax.php
response: false
這裏是我的JS:
<script id="source" language="javascript" type="text/javascript">
$(function() {
$('#url').bind('input', function() {
$(this).val() // get value
$.ajax({
type: 'POST',
url: 'functions/ajax.php',
data: {
url: $('#url').val()
},
success: function (data) //on receive of reply
{
$(function() {
$.ajax({
url: 'functions/ajax.php', //the script to call to get data
data: "", //you can insert url arguments here to pass to api.php
//for example "id=5&parent=6"
dataType: 'json', //data format
success: function (data) //on receive of reply
{
var namePHP = data[1];
var categoryPHP = data[2];
//--------------------------------------------------------------------
// 3) Update html content
//--------------------------------------------------------------------
$('#name').html(namePHP); // # name and #category are input fields I want autofilled
$('#category').html(categoryPHP);
}
});
});
}
});
});
});
</script>
ajax.php
<?php
require_once ('DBconnect.php');
$url = $_POST['url'];
$url = mysqli_real_escape_string($con, $url);
$query = "SELECT * FROM `inserted_posts` WHERE `search_name` = '$url'";
$result = mysql_query($query);
$array = mysql_fetch_array($result);
echo json_encode($array);
?>
爲什麼你的回調做一個AJAX調用同一個頁面拉AJAX呼叫? – 2013-04-24 18:19:20
@RocketHazmat:爲什麼不呢?不同的方法,參數和數據類型:-) – Bergi 2013-04-24 18:29:48
[希望自動填充輸入欄與AJAX](http://stackoverflow.com/questions/16199886/want-to-auto-fill-input-bars-with- ajax) – Musa 2013-04-24 23:40:47