Dim adoconn As New ADODB.Connection
Dim rs As New ADODB.Recordset
Private Sub Form_Load()
Dim str As String
Set adoconn = Nothing
Text2.Text = Form4.List2.Text
adoconn.Open "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=Database1.mdb;Persist Security Info=False"
str = "select * from dept where DEPT =" & Form4.List2.Text
rs.Open str, adoconn, adOpenDynamic, adLockPessimistic
Text1.Text = rs(2)
End Sub
rs.open
聲明有什麼問題??? 它以完美的形式爲我工作。 但它以另一種形式給出運行時錯誤:沒有爲一個或多個參數給出值...VB6 recordset.open沒有給出一個或多個參數錯誤的值
你確定'Form4.List2.Text'有完成查詢的值嗎? – Xint0 2011-03-14 08:20:45
表單引用是否正確? – ramu 2011-03-14 08:48:02
是的...它正確的我從列表框中獲得的值在form4 – user658427 2011-03-14 09:37:56