Bash變量中的Imagemagick參數沒有正確解釋？

Question

我需要使用Imagemagick以畫布作爲基礎和其他一些圖像來構成一幅圖像。

目前，最簡單的場景只是工作（請注意，您將需要一個名爲src1.png和src2.png兩個圖像這個工作）：

convert src1.png -gravity northwest -draw 'image Over 10,10 0,0 "src2.png"' result.png 

不過，我需要dinamically僞造這些參數能夠在src1.png的頂部繪製一個，兩個或多個圖像。

爲此，我嘗試將參數存儲在變量中，然後進行替換。我想這兩個版本，都與陣列或簡單的字符串：

DRAWOPTS=(-draw 'image Over 10,10 0,0 \"src2.png\"') 
convert src1.png -gravity northwest ${DRAWOPTS[@]} result.png 

DRAWOPTS="-draw 'image Over 10,10 0,0 \"src2.png\"'" 
convert src1.png -gravity northwest $DRAWOPTS result.png 

但我總是得到這些錯誤：

convert.im6: non-conforming drawing primitive definition `image' @ error/draw.c/DrawImage/3160. 
convert.im6: unable to open image `Over': No such file or directory @ error/blob.c/OpenBlob/2641. 
convert.im6: no decode delegate for this image format `Over' @ error/constitute.c/ReadImage/544. 
convert.im6: unable to open image `10,10': No such file or directory @ error/blob.c/OpenBlob/2641. 
convert.im6: no decode delegate for this image format `10,10' @ error/constitute.c/ReadImage/544. 
convert.im6: unable to open image `0,0': No such file or directory @ error/blob.c/OpenBlob/2641. 
convert.im6: no decode delegate for this image format `0,0' @ error/constitute.c/ReadImage/544. 
convert.im6: unable to open image `"src2.png"'': No such file or directory @ error/blob.c/OpenBlob/2641. 
convert.im6: no decode delegate for this image format `"src2.png"'' @ error/constitute.c/ReadImage/544. 
convert.im6: non-conforming drawing primitive definition `image' @ error/draw.c/DrawImage/3160. 

我不能得到這個工作。需要這個引用地獄的一些幫助，請。

Answer 1

您需要引用數組的擴展。

DRAWOPTS=(-draw 'image Over 10,10 0,0 "src2.png"') 
convert src1.png -gravity northwest "${DRAWOPTS[@]}" result.png