將用戶輸入的單詞放入java中的二維數組中

Question

我在嘗試在二維數組中輸入用戶輸入的單詞時遇到了困難。 我的程序需要做的是創建一個單詞搜索難題，提示用戶他或她想找到多少單詞，以及給定的單詞將會是什麼。我遇到的麻煩是我似乎無法將用戶的輸入放入2d數組中。下面是我當前的代碼：

public static void generate(){ 
     int rows = 5; 
     int columns = 5; 
     char[][] table = new char [rows][columns]; 
     int numberwanted; 

     System.out.println("Type in the number of words you want to generate: "); 
     numberwanted = userinput.nextInt(); 
     System.out.println("Type in the words you want to generate: "); 
     for (int i = 0; i < numberwanted; i++){ 
     String words = userinput.next(); 
     char te = words.charAt(i); 
     for(int r = 0; r < rows; r++){ 
      for(int c = 0; c < columns; c++){ 
       table[r][c] = te; 
       System.out.print(table[r][c] + " "); 
      } 
      System.out.println(); 
     } 

     }// forloop 

輸出：

Type in the number of words you want to generate: 
2 
Type in the words you want to generate: 
test 
t t t t t 
t t t t t 
t t t t t 
t t t t t 
t t t t t 

目標輸出：

Type in the number of words you want to generate: 
2 
Type in the words you want to generate: 
test 
hi 
t e s t x   x x t x x 
x x x x x or x x e x x and so on... with x's being empty 
x h x x x   x x s x x 
x i x x x   x x t x x 
x x x x x   x x h i x 

Answer 1

我調整了整個程序有點使其更加堅固。它如何工作：

• 處理table的每一行。
• 如果用戶想提供一個單詞，請求單詞。
• 在當前的row處添加單詞（可能被截斷）。
• 如果需要的話，可以在x的右邊填一行。

，最後使整個table。

private static int ROWS = 5; 
private static int COLUMNS = 5; 

public static void main(String[] args) { 
    char[][] table = new char[ROWS][COLUMNS]; 
    int numberwanted; 
    try (Scanner in = new Scanner(System.in)) { 
     System.out.println("Type in the number of words you want to generate: "); 
     numberwanted = Math.min(in.nextInt(), ROWS); 

     for (int row = 0; row < ROWS; row++) { 
      String word = null; 
      if (row < numberwanted) { 
       System.out.println(String.format("Type in the %d. word: ", row)); 
       word = in.next(); 
      } 
      for (int col = 0; col < COLUMNS; col++) { 
       table[row][col] = word != null && word.length() > col ? word.charAt(col) : 'x'; 
      } 
     } 
    } 
    renderGrid(table); 
} 

private static void renderGrid(char[][] grid) { 
    for (int row = 0; row < ROWS; row++) { 
     for (int col = 0; col < COLUMNS; col++) { 
      System.out.print(grid[row][col] + " "); 
     } 
     System.out.println(); 
    } 
} 

Answer 2

您需要更新的字符串中的所有字符。在你的情況下，你只有字符串的第一個字符。

public static void generate(){ 
      int rows = 5; 
      int columns = 5; 
      char[][] table = new char [rows][columns]; 
      int numberwanted; 
      Scanner sc = new Scanner(System.in); 
      System.out.println("Type in the number of words you want to generate: "); 
      numberwanted = sc.nextInt(); 
      System.out.println("Type in the words you want to generate: "); 
      int j=0; 
      for (int i = 0; i < numberwanted; i++){ 
      String words = sc.next(); 
      char te = ' '; 
      for(int r = 0; r < rows; r++){ 
       for(int c = 0; c < columns; c++){ 
        if(j<words.length()) te = words.charAt(j++); 
        else te = '*'; 
        table[r][c] = te; 
        System.out.print(table[r][c] + " "); 

       } 
       System.out.println(); 
      } 

      } 
} 

更新。 另外，如果你只想要對角元素。下面是它

public static void generate(){ 
      int rows = 5; 
      int columns = 5; 
      char[][] table = new char [rows][columns]; 
      int numberwanted; 
      Scanner sc = new Scanner(System.in); 
      System.out.println("Type in the number of words you want to generate: "); 
      numberwanted = sc.nextInt(); 
      System.out.println("Type in the words you want to generate: "); 
      int j=0; 
      for (int i = 0; i < numberwanted; i++){ 
      String words = sc.next(); 
      char te = ' '; 
      for(int r = 0; r < rows; r++){ 
       for(int c = 0; c < columns; c++){ 
        if(j<words.length() && r==c) te = words.charAt(j++); 
        else te = '*'; 
        table[r][c] = te; 
        System.out.print(table[r][c] + " "); 

       } 
       System.out.println(); 
      } 

      } 
} 

希望這有助於