在下面的代碼中,$ datastring變量中的JSON在JSONLint上作爲有效的JSON傳遞。JSONLint和PHP之間的差異JSON_DECODE
但是,使用PHP的json_encode時出現語法錯誤。
我能做些什麼來解決這個問題?我試過剝掉斜槓,但得到相同的錯誤。
$datastring = '[{"Program": 3034370,"Column": "CLI_RID","Value": "1006278"},{"Program": 3034370,"Column": "Filename","Value": "\\\\henery\\1006278\\CONFIRMATION LETTER AVAILABLE.html"},{"Program": 3034370,"Column": "EVENT_CODE","Value": "20120725ZZAQ"},{"Program": 3034370,"Column": "DOC_NAME","Value": "Confirmation Email"},{"Program": 3034370,"Column": "PrintDate","Value": "20120410"},{"Program": 2959623,"Column": "ISSUE","Value": "Res Spring"},{"Program": 2959623,"Column": "FILENAME","Value": "~/Res/Mag.aspx?I=res_spring&P=1006278"}]';
$data = json_decode($datastring, true);
// Define the errors.
$json_errors = array(
JSON_ERROR_NONE => 'No error has occurred',
JSON_ERROR_DEPTH => 'The maximum stack depth has been exceeded',
JSON_ERROR_CTRL_CHAR => 'Control character error, possibly incorrectly encoded',
JSON_ERROR_SYNTAX => 'Syntax error',
);
if(!$data) {
echo 'Last error : '. $json_errors[json_last_error()]. PHP_EOL. PHP_EOL;
} else {
echo print_r($data, true);
}
我將從ASP.Net頁面獲取此JSON字符串。
反斜槓已經翻了一番。 – MB34 2012-08-14 20:38:57
不,他們不是。該代碼包含PHP文字''「\\\\ henery \\ 1006278 \\ CONFIRMATION LETTER AVAILABLE.html」'',這是字符串'「\\ henery \ 1006278 \ CONFIRMATION LETTER AVAILABLE.html」'。在JSON中,字符串中的反斜槓必須被轉義,而'\ 1'是一個無效的文字。 – phihag 2012-08-15 05:41:52