從Swift APP解析php文件接收值時出錯Error

-1

我的swift應用程序有問題，應用程序必須與服務器上的php文件進行通信，我的問題是，上面的參數到達PHP文件的swift代碼是以下內容：可選（「[email protected]」），可選（「pippo」）。現在我的問題是，怎樣才能得到這些參數到PHP文件，而不字符可選（「...」）從Swift APP解析php文件接收值時出錯Error

SWIFT CODE：

var ris=""; 
     //created URL 
     guard let requestURL = URL(string: URL_SAVE_TEAM) else { return "no" } 

     //creating URLRequest 
     var request = URLRequest(url: requestURL) 

     //setting the method to post 
     request.httpMethod = "POST" 

     //getting values from text fields 


     //creating the post parameter by concatenating the keys and values from text field 
     let postParameters = "email=\(email)&password=\(password)" 

     //adding the parameters to request body 
     request.httpBody = postParameters.data(using: .utf8) 

     //creating a task to send the post request 
     let session = URLSession.shared 

     let task = session.dataTask(with: request) { 
      data, response, error in 

      guard error == nil else { 
       print("error is \(error!.localizedDescription)") 
       return 
      } 

      guard let data = data else { 
       print("No data was returned by the request!") 
       return 
      } 

      //parsing the response 
      do { 
       //converting resonse to NSDictionary 
       let myJSON = try JSONSerialization.jsonObject(with: data, options: .allowFragments) as? Dictionary<String, String?> 

       //parsing the json 
       guard let parseJSON = myJSON, let msg = parseJSON["message"] as? String else { 
        print("Error parsing data") 
        return 
       } 

       //printing the response 
       print(msg) 

       ris=msg; 

      } catch { 
       print(error) 
      } 

     } 

     //executing the task 
     task.resume() 


     return ris;

PHP代碼：

<?php 

include 'user.php'; 

header('Content-Type: application/json'); 
$email= $_POST['email']; 
$password = $_POST['password']; 
$ris['message']=""; 

$user = new User(); 

//procedo con il login 
if($user->login($email,$password,"MOBILE")==true){ 
    $ris['message']="yes"; 
} 


else{ 
    $ris['message']="no"; 
} 

echo json_encode($ris); 

?>

來源

2017-05-31 riki

簡短的回答是：

email和password是選項ALS，需要解開

let postParameters = "email=\(email!)&password=\(password!)"

但是，如果這兩個變量，以任何理由都是nil，您的應用程序會崩潰。

有StackOverflow上幾個答案： How do you unwrap Swift optionals? 但你可以閱讀更多的也是在這裏：

Apple - Optional Chaining

或

https://gist.github.com/patricklynch/689525d466c4ada42b8e

來源

2017-05-31 15:45:42 mat

現在我嘗試用你的代碼 – riki

我想你代碼但沒有改變任何東西 – riki

它開始感謝 – riki

從Swift APP解析php文件接收值時出錯Error

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