計算SQL字符串值中某個字符的出現次數？

Question

如果你有電子郵件地址

you.late.you@asdf.com 

you_late_you@asdf.com 

你是如何讓，如果你有2個點來算/通過使用SQL代碼強調？

Answer 1

select len('you.late.you@asdf.com') - len(replace('you.late.you@asdf.com', '.', '')) 

Answer 2

這會給你想要的結果。

DECLARE @str VARCHAR(1000) 
SET @str = 'you.l_ate.you@as_df.com' 
SELECT (LEN(@str)- LEN(REPLACE(@str ,'.' ,'')))+(LEN(@str)- LEN(REPLACE(@str ,'_' ,''))) 

回答：5

Answer 3

如果要算的是有兩個.或_行數，你可以做到以下幾點：

select count(*) 
    from mytable 
where left(email, charindex('@', email)) like '%[._]%[._]%' 

的left和charindex用於忽略域名（其將具有.）。

參考：LIKE (TSQL, SQL Server 2008)

Answer 4

我認爲他想的@前計數不點的字母：

declare @myEmail varchar(50) 
set @myEmail = 'you.late.you@asdf.com' 

declare @mySearch varchar(50) 
set @mySearch = SUBSTRING (@myEmail,0 , PATINDEX('%@%',@myEmail)) 
select (LEN(REPLACE(@mySearch, '.', ''))) 

Answer 5

select 
    length(substr('you.late.you@asdf.com',1,INSTR('you.late.you@asdf.com','@',1))) - 
    length(replace(substr('you.late.you@asdf.com',1,INSTR('you.late.you@asdf.com','@',1)), '.', '')) 
from dual