二次方程的問題

Question

下面的代碼是我用於二次問題求解器的地方，其中a不能等於0.我目前得到了非常奇怪的答案，並且似乎無法找出問題所在。思考？

def descriminant(a, b, c): #Setting input perameters for descriminant 
if a>0 or a<0: #If a isnt equal to 0, find descriminant 
    disc = (b**2-4*a*c) #Defining what descriminant does with disc 
    if disc>0: 
     disc1=float(disc)**0.5 
     return disc1 #returns and allows to be used again instead of print which doesnt allow you to use it again 

    else: 
     print("The discriminant must be greater than 0") 
else: #if a is equal to 0 
    print ("A cannot equal 0") #Tell the user a cant equal 0 


def quad_form(a, b, c): #Defining quad form w/ input a, b, c 

disc2=float(descriminant(a, b, c)) 


quad_form1=((-1*b) + disc2/float((2*a))) #Defining + forumula for quad form 
quad_form2=((-1*b) - disc2/float((2*a))) #Defining - forumula for quad form 

return quad_form1, quad_form2 


UI=input("Enter the coefficients of a quadratic separated by commas where A is not equal to zero: ") #User Input 
a=float(UI[0]) 
b=float(UI[1]) 
c=float(UI[2]) 

print quad_form(a, b, c) 

Answer 1

它看起來像你平方根兩次。一旦在​​，然後在quad_form()。你應該刪除其中的一個。

編輯： 你quad_form表達式也是錯誤的：

quad_form1=((-1*b) + disc3/float((2*a))) 

應該

quad_form1=((-1*b) + disc3)/float((2*a)) 

或者其可讀性

quad_form1=(-b + disc3)/float(2*a). 

同樣，對於下一行，

quad_form1=((-1*b) - disc3)/float((2*a))