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我想知道如何創建一個窗口使用Win32 API與特定的客戶區大小。WinAPI:創建一個窗口與指定的客戶區大小
當嘗試使用下面的代碼創建一個窗口,整個窗口爲640x480,與窗口的鉻服用一些客戶區:
HWND hWnd;
WNDCLASSEX WndClsEx;
ZeroMemory(&WndClsEx, sizeof(WNDCLASSEX));
WndClsEx.cbSize = sizeof(WNDCLASSEX);
WndClsEx.style = CS_HREDRAW | CS_VREDRAW;
WndClsEx.lpfnWndProc = DefWindowProc;
WndClsEx.cbClsExtra = 0;
WndClsEx.cbWndExtra = 0;
WndClsEx.hIcon = LoadIcon(NULL, IDI_APPLICATION);
WndClsEx.hCursor = LoadCursor(NULL, IDC_ARROW);
WndClsEx.hbrBackground = (HBRUSH)GetStockObject(WHITE_BRUSH);
WndClsEx.lpszMenuName = NULL;
WndClsEx.lpszClassName = TEXT("Title");
WndClsEx.hInstance = hInstance;
WndClsEx.hIconSm = LoadIcon(NULL, IDI_APPLICATION);
RegisterClassEx(&WndClsEx);
hWnd = CreateWindowEx( NULL,
TEXT("Title"),
TEXT("Title"),
WS_OVERLAPPEDWINDOW,
CW_USEDEFAULT,
CW_USEDEFAULT,
640,
480,
NULL,
NULL,
hInstance,
NULL);
假設簡單的數學不會很解決問題,我如何考慮鉻的大小?
注:我使用SDL創建窗口後,但我猜它一定的窗口大小,並使得它的大小沒有區別。
更正時,它根據客戶區的座標計算窗口區域的座標。 – 2011-01-30 16:17:16