-2
我有一個HTML表單和PHP代碼我有:警告:缺少參數?
function Users($user, $pass, $name, $email){
if(empty($user)) return false;
if(empty($pass)) return false;
if(empty($name)) return false;
if(empty($email)) return false;
$queryr = "INSERT INTO users (Username, Password, Name, Email) VALUES ('".$user."', '".base64_encode($pass)."', '".$name."', '".$email."')";
}
if ($_SERVER['REQUEST_METHOD'] == 'POST'){
if(QUsers(isset($_POST[$user])) && (isset($_POST[$name])) && (isset($_POST[$name])) && (isset($_POST[$email]))){
mysqli_query($sqlc2,$queryr);
if (isset($_SERVER['username'])){
echo '<div id="errorUsername">Error</div>';
}else{
$_SERVER['username'] = $user;
}
}else{
echo '<div id="ErrorUsername">Error</div>';
}
}
而且在視結果的那一刻,我看到:
Warning: Missing argument 2 for QUsers(), called
好吧,我試試吧。謝謝。 – 2014-09-20 06:25:05
嘿,現在你工作得非常棒。 – 2014-09-20 06:26:24