PHP MySQL查詢不返回預期的結果

Question

的全套，我有以下mysql_query我已經放在一個PHP變量：

$equalDimensions_query = 
"SELECT 'allEqual' AS COL1,COUNT(*) AS imgCount FROM (
    SELECT imgHeight, imgWidth, imgId AS primaryId FROM primary_images 
    UNION ALL 
    SELECT imgHeight, imgWidth, primaryId FROM secondary_images 
) AS union_table 
WHERE primaryId = $imgId AND imgWidth = $maxImageWidth AND imgHeight = $maxImageHeight 
UNION ALL 
SELECT 'widthEqual' AS COL1,COUNT(*) AS imgCount FROM (
    SELECT imgHeight, imgWidth, imgId AS primaryId FROM primary_images 
    UNION ALL 
    SELECT imgHeight, imgWidth, primaryId FROM secondary_images 
) AS union_table 
WHERE primaryId = $imgId AND imgWidth = $maxImageWidth AND imgHeight != $maxImageHeight 
UNION ALL 
SELECT 'heightEqual' AS COL1,COUNT(*) AS imgCount FROM (
    SELECT imgHeight, imgWidth, imgId AS primaryId FROM primary_images 
    UNION ALL 
    SELECT imgHeight, imgWidth, primaryId FROM secondary_images 
) AS union_table 
WHERE primaryId = $imgId AND imgWidth != $maxImageWidth AND imgHeight = $maxImageHeight"; 

我使用下面的PHP將這些結果放入一個單關聯數組：

$equalDimensions_data = mysql_query($equalDimensions_query) or die('MySql Error' . mysql_error()); 

while ($row = mysql_fetch_assoc($equalDimensions_data)) { 
    $cnt[$row['COL1']] = $row['imgCount']; 
} 

它是假設返回一組三個陣列與值第一個是第一個，第二個是widthEqual，第三個是heightEqual（順序無關緊要）。

唉由於某種原因它是不返回allEqual：

Array 
(
    [heightEqual] => 0 
    [widthEqual] => 0 
) 

當我使用print_r原文「三陣列」的形式顯示檢索到的數據，我得到的只有相同的結果陣列：

Array 
(
    [COL1] => heightEqual 
    [imgCount] => 0 
) 
Array 
(
    [COL1] => widthEqual 
    [imgCount] => 0 
) 

然而，如果我用print_r沒有循環如下：

$equalDimensions_data = mysql_query($equalDimensions_query) or die('MySql Error' . mysql_error()); 
$equalDimensions_array = mysql_fetch_assoc($equalDimensions_data); 

print("<pre>"); 
print_r($equalDimensions_array); 
print("</pre>"); 

我回到了以前缺少allEqual陣列：

Array 
(
    [COL1] => allEqual 
    [imgCount] => 2 
) 

據我所知，因爲沒有在該while循環的最後一種情況，我只返回一個的結果;但爲什麼呢，在while循環的情況下，allEqual的結果似乎被跳過了？這是我的代碼問題嗎？我感謝您提供的任何幫助。對於這樣一個長期的問題，我表示歉意。我想確保儘可能提供儘可能多的信息。

---

你可以在這裏下載我的數據庫模式：https://files.me.com/stefanmelnychenko/453l4z

Answer 1

這是你複製。您不會更改變量或任何內容，以便複製任何錯誤（如果有）。

我檢查你的schemma和一切都很好，這是一個PHP腳本：

<?PHP 

// Make a MySQL Connection 
mysql_connect("localhost", "root", "") or die(mysql_error()); 

//select database 
mysql_select_db("new_arrivals_imgs") or die(mysql_error()); 


$imgId=1; 
$maxImageHeight=1; 
$maxImageWidth=1; 

$equalDimensions_query = 
"SELECT 'allEqual' AS COL1,COUNT(*) AS imgCount FROM (
    SELECT imgHeight, imgWidth, imgId AS primaryId FROM primary_images 
    UNION ALL 
    SELECT imgHeight, imgWidth, primaryId FROM secondary_images 
) AS union_table 
WHERE primaryId = $imgId AND imgWidth = $maxImageWidth AND imgHeight = $maxImageHeight 
UNION ALL 
SELECT 'widthEqual' AS COL1,COUNT(*) AS imgCount FROM (
    SELECT imgHeight, imgWidth, imgId AS primaryId FROM primary_images 
    UNION ALL 
    SELECT imgHeight, imgWidth, primaryId FROM secondary_images 
) AS union_table 
WHERE primaryId = $imgId AND imgWidth = $maxImageWidth AND imgHeight != $maxImageHeight 
UNION ALL 
SELECT 'heightEqual' AS COL1,COUNT(*) AS imgCount FROM (
    SELECT imgHeight, imgWidth, imgId AS primaryId FROM primary_images 
    UNION ALL 
    SELECT imgHeight, imgWidth, primaryId FROM secondary_images 
) AS union_table 
WHERE primaryId = $imgId AND imgWidth != $maxImageWidth AND imgHeight = $maxImageHeight"; 

$equalDimensions_data = mysql_query($equalDimensions_query) 
or die('MySql Error' . mysql_error()); 

while ($row = mysql_fetch_assoc($equalDimensions_data)) { 
    $cnt[$row['COL1']] = $row['imgCount']; 
} 

print_r($cnt); 

?> 

，這是結果：