PHP的MySQL只選擇匹配列

Question

  Mysql Database- 

     id | username | folder_name | 
      1 | ashly | Folder  | 
      2 | ashly |    | 
      3 | ashly |    | 
      4 | ashly | Folder  | 
      5 | ashly | Folder  | 
      6 | ashly | Folder 1 | 
      7 | ashly | Folder 2 | 


      $sql = mysql_query("SELECT `id`, `username`, `title`, LEFT(`description`, 90) as `description`, `file`, `code`, `folder_name`, `type`, `size`, `date` FROM `files` WHERE `username` = '$userfile' AND `folder_name` > '' ORDER BY `id` DESC LIMIT 1, 5"); 


     while ($query_row = mysql_fetch_array($sql2)) { 
      $filefolder = $query_row['folder_name']; 
      $filetitle = $query_row['title'];   
      $filecode = $query_row['code']; 
      $filedesc = $query_row['description']; 
      $filefile = $query_row['file']; 
      $filesize = $query_row['size']; 
      $filedate = $query_row['date']; 
      $filetype = $query_row['type']; 

//這裏我環路結果

 if (empty($filefolder) === false) { 
    echo "" . $filefolder . "<div id='imageshowsearch'><div id='linkstyle'><strong><a href='http://localhost/edu/1111111111111/userdownload.php?code=". $filecode . " '><img src='files/thumbs/" . $filecode . "/" . $filefile . "' alt=" . $filetitle . ">" . $filetitle . "</strong></div></a></div>"; 

    //here print result 
      } 
      } 

我不能表現出從文件夾folder_name只有once.With 5張圖片。|當我循環它的MySQL結果。

 Result: 

    folder  | folder   | folder   | folder 1  | folder 2 
    here is image | here is image | here is image | here is image | here is image 

    I wonna get this result:  

    folder   | 
    here is image | here is image | here is image | 

    folder 1  | 
    here is image | 

    folder 2  | 
    here is image | 

我沒有主意。如何只顯示文件夾名稱一次，並在文件夾名稱下顯示來自某個文件夾的最多5個圖像。只是我不想重複每個圖像的文件夾名稱。我必須將文件夾名稱與文件夾圖像與用戶圖像分組。我的問題是隻爲這些文件夾名稱重複...感謝支持我寫，因爲網站不允許我發佈我的問題'更多的代碼沒有解釋'

Answer 1

您可以使用以下方法。希望它能爲你工作。

$sql = mysql_query("SELECT DISTINCT `folder_name` FROM `files` WHERE `username` = '$userfile' AND `folder_name` > ''"); 
while ($row = mysql_fetch_array($sql)) { 
$folder== $row['folder_name']; 

$sql2 = mysql_query("SELECT `id`, `username`, `title`, LEFT(`description`, 90) as `description`, `file`, `code`, `type`, `size`, `date` FROM `files` WHERE folder_name`='$folder' ORDER BY `id` DESC LIMIT 1, 5"); 

//Here you can echo $folder i.e, folder name and then all its image 
     while ($query_row = mysql_fetch_array($sql2)) { 
      $filetitle = $query_row['title'];   
      $filecode = $query_row['code']; 
      $filedesc = $query_row['description']; 
      $filefile = $query_row['file']; 
      $filesize = $query_row['size']; 
      $filedate = $query_row['date']; 
      $filetype = $query_row['type']; 
} 

} 

祝你好運。