yii2搜索鏈接到同一個表的兩個字段

Question

我試圖在網格視圖中執行搜索，如解釋here。當你有一個關聯到特定表的單個字段時，這種技術可以正常工作。但是，我有一個表包含與另一個表（資源）有關係的兩個字段（resource_to_id，resource_from_id）。

在下面的模型代碼中，我可以使用$ query-> joinwith行來搜索該字段，但不能同時使用兩者。我如何實現搜索這兩個資源字段？

<?php 

namespace app\models; 

use Yii; 
use yii\base\Model; 
use yii\data\ActiveDataProvider; 
use app\models\Messages; 

/** 
* MessagesSearch represents the model behind the search form about `app\models\Messages`. 
*/ 
class MessagesSearch extends Messages 
{ 
    /** 
    * @inheritdoc 
    */ 
    public function rules() 
    { 
     return [ 
      [['id', 'message_read'], 'integer'], 
      [['subject', 'message', 'time_sent', 'resource_to_id', 'resource_from_id'], 'safe'], 
     ]; 
    } 

    /** 
    * @inheritdoc 
    */ 
    public function scenarios() 
    { 
     // bypass scenarios() implementation in the parent class 
     return Model::scenarios(); 
    } 

    /** 
    * Creates data provider instance with search query applied 
    * 
    * @param array $params 
    * 
    * @return ActiveDataProvider 
    */ 
    public function search($params) 
    { 
     $query = Messages::find(); 

     // add conditions that should always apply here 

     $dataProvider = new ActiveDataProvider([ 
      'query' => $query, 
     ]); 

     $this->load($params); 

     if (!$this->validate()) { 
      // uncomment the following line if you do not want to return any records when validation fails 
      // $query->where('0=1'); 
      return $dataProvider; 
     } 

     $query->joinwith('resourceFrom'); 
     //$query->joinwith('resourceTo'); 

     // grid filtering conditions 
     $query->andFilterWhere([ 
      'id' => $this->id, 
      'time_sent' => $this->time_sent, 
      'message_read' => $this->message_read, 
     ]); 

     $query->andFilterWhere(['like', 'subject', $this->subject]) 
      ->andFilterWhere(['like', 'message', $this->message]) 
      ->andFilterWhere(['like', 'resources.resource_name', $this->resource_to_id]) 
      ->andFilterWhere(['like', 'resources.resource_name', $this->resource_from_id]) 
      ; 

     return $dataProvider; 
    } 
} 

Answer 1

的搜索功能，你需要使用的別名連接表是這樣的：

$query->joinWith(['resourceFrom from', 'resourceTo to']); 

然後修復andFilterWhere條件：

$query->andFilterWhere(['like', 'from.resource_name', $this->resource_from_id]) 
    ->andFilterWhere(['like', 'to.resource_name', $this->resource_to_id]);