將列表分成兩列

Question

我有我想要從數據庫中獲取的值列表。所以列表很長我想在兩列中獲取列表。我怎樣才能把它分成兩列。例如.. aphabets

A  |  B 
C  |  D 
E  |  F 
G  |  H 
I  |  J 
K  |  L 

以這種方式

服用名單。我用下面的方法...

<?php 
    $sql = mysql_query("SELECT * FROM poet WHERE status='Publish' ORDER BY name ") or die(mysql_error()); 
    $total_rows = mysql_num_rows($sql); 


    $i = 1; 
    $j = ceil($total_rows/2); 

    while ($i <= $j) { 
     $result = mysql_fetch_assoc($sql); 
?> 

<tr>  
    <? if($i%2 == 0) { ?> 
     <td class="navigation"><?php echo fetch_table_poet($result["pid"], 1, 3); ?></td> 
    <? } elseif($i%2 != 0) { ?> 
     <td class="navigation"><?php echo fetch_table_poet($result["pid"], 1, 3); ?></td> 
    <? } ?> 
</tr> 

<?php $i++; } ?> 

它給我以這種方式輸出..

A | A 
B | B 
C | C 

注意 - 我想用PHP不使用任何的jQuery或JavaScript來做到這一點。

Answer 1

我建議jQuery的columnizer作爲一個解決問題的方法http://welcome.totheinter.net/columnizer-jquery-plugin/

Answer 2

似乎每一次循環你重置你的結果。在時間之外設置$結果。更接受的方式來做到這一點是：

while ($row = mysql_fetch_assoc($sql)){ 


} 

然後測試$我，看它是否被2整除（這意味着你有2列，需要添加行和新的行代碼開始的結束）。

if($i%2 == 0){ 
    echo '</tr><tr>'; 
} 

Answer 3

嘗試：

<?php 
    $sql = mysql_query("SELECT * FROM poet WHERE status='Publish' ORDER BY name ") or die(mysql_error()); 

$i = 0; 
$total_rows = mysql_num_rows($sql); 

    while ($result = mysql_fetch_assoc($sql)) { 
     $i++; 
?> 


    <? if($i&1 == 1) { ?> 
<tr> 
     <td class="navigation"><?php echo $result["pid"]; ?></td> 
    <? } elseif($i&1 == 0) { ?> 
     <td class="navigation"><?php echo $result["pid"]; ?></td> 
</tr> 
    <? } 
if($i == $total_rows && $total_rows&1 == 1){ echo "</tr>"; } ?> 


<?php } ?> 

編輯：Bug修復..

我覺得Colmn行這會工作：

<?php 
    $sql = mysql_query("SELECT * FROM poet WHERE status='Publish' ORDER BY name ") or die(mysql_error()); 
    $total_rows = mysql_num_rows($sql); 

    $iOne = 1; 
    $iTwo = floor($totalRows/2); 

    foreach($iOne=1,$iTwo=ceil($totalRows/2); $iTwo < $total_rows; $iOne++,$iTwo++){ 
     ?> 
     <tr>  
      <td class="navigation"><?php echo mysql_result($sql,$iOne,'pid') ?></td> 
      <td class="navigation"><?php echo mysql_result($sql,$iTwo,'pid') ?></td> 
     </tr> 
     <?php  
    } 
?> 

Answer 4

最後我成功的代碼。

<?php 
    $sql = mysql_query("SELECT * FROM poet WHERE status='Publish' ORDER BY name ") or die(mysql_error()); 
    $total_rows = mysql_num_rows($sql); 
    $i = 1; 
    while ($result = mysql_fetch_assoc($sql)) { ?> 

     <?php if($i%2 == '1') { ?> 
      <tr>  
        <td class="navigation"><?php echo fetch_table_poet($result["pid"], 1, 3); ?></td> 
     <?php } elseif($i%2 == '0') { ?> 
        <td class="navigation"><?php echo fetch_table_poet($result["pid"], 1, 3); ?></td> 
      </tr>      
     <?php } ?> 

    <?php $i++; } ?>