2017-04-23 51 views
2

我想創建一個多語言的應用程序,但我的主頁是由圖像和textViews組成的gridView。當我創建一個Java列表(像這樣):gridView - 在strings.xml中的數組

String textoList[] = {"Visto", "Alojamento", "C.P.F.", "Alimentação", "Carteirinha", "Guia", "Registro", "Informações", "Assistência", "Biblioteca", "Calendário", "Transporte", "INT", "Intérprete", "F.A.Q."}; 

它工作得很好。但是我意識到我不應該在Java中創建一個列表,而是使用一個已經在strings.xml文件中創建的數組,以便我的應用程序可以被翻譯。基本上,我想要這個數組的文本。我怎樣才能做到這一點?

有人可以幫我一下嗎?如果有人想對它進行測試,完整的代碼是:

package br.com.unbparaestrangeiros.unbparaestrangeiros; 

import android.app.Activity; 
import android.content.Intent; 
import android.content.res.Resources; 
import android.os.Bundle; 
import android.view.View; 
import android.widget.AdapterView; 
import android.widget.GridView; 

public class MainActivity extends Activity{ 
    GridView gridView; 

    Resources r = getResources(); 
    String[] textoList = r.getStringArray(R.array.itens); 

    //String textoList[] = {"Visto", "Alojamento", "C.P.F.", "Alimentação", "Carteirinha", "Guia", "Registro", "Informações", "Assistência", "Biblioteca", "Calendário", "Transporte", "INT", "Intérprete", "F.A.Q."}; 

    int textoImagem[] = {R.drawable.visto, R.drawable.alojamento, R.drawable.cpf, R.drawable.alimentacao, R.drawable.carteirinha, R.drawable.guia, R.drawable.registro, R.drawable.informacoes, R.drawable.assistencia, R.drawable.biblioteca, R.drawable.calendario, R.drawable.transporte, R.drawable.informacoes, R.drawable.interprete, R.drawable.perguntas}; 

    @Override 
    public void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.inicio); 

     gridView = (GridView) findViewById(R.id.gridView); 

     GridAdapter adapter = new GridAdapter(MainActivity.this, textoImagem, textoList); 

     gridView.setAdapter(adapter); 

     gridView.setOnItemClickListener(new AdapterView.OnItemClickListener() { 
      @Override 
      public void onItemClick(AdapterView<?> parent, View view, int position, long id) { 
       switch (position) { 
        case 0: 
         Intent case0 = new Intent(MainActivity.this, Visto.class); 
         startActivity(case0); 
         break; 

        case 1: 
         Intent case1 = new Intent(MainActivity.this, Alojamento.class); 
         startActivity(case1); 
         break; 

        case 2: 
         Intent case2 = new Intent(MainActivity.this, CPF.class); 
         startActivity(case2); 
         break; 

        case 3: 
         Intent case3 = new Intent(MainActivity.this, Alimentacao.class); 
         startActivity(case3); 
         break; 

        case 4: 
         Intent case4 = new Intent(MainActivity.this, Carteirinha.class); 
         startActivity(case4); 
         break; 

        case 5: 
         Intent case5 = new Intent(MainActivity.this, Guia.class); 
         startActivity(case5); 
         break; 

        case 6: 
         Intent case6 = new Intent(MainActivity.this, Registro.class); 
         startActivity(case6); 
         break; 

        case 7: 
         Intent case7 = new Intent(MainActivity.this, Informacoes.class); 
         startActivity(case7); 
         break; 

        case 8: 
         Intent case8 = new Intent(MainActivity.this, Assistencia.class); 
         startActivity(case8); 
         break; 

        case 9: 
         Intent case9 = new Intent(MainActivity.this, Biblioteca.class); 
         startActivity(case9); 
         break; 

        case 10: 
         Intent case10 = new Intent(MainActivity.this, Calendario.class); 
         startActivity(case10); 
         break; 

        case 11: 
         Intent case11 = new Intent(MainActivity.this, Transporte.class); 
         startActivity(case11); 
         break; 

        case 12: 
         Intent case12 = new Intent(MainActivity.this, Assessoria.class); 
         startActivity(case12); 
         break; 

        case 13: 
         Intent case13 = new Intent(MainActivity.this, Interprete.class); 
         startActivity(case13); 
         break; 

        case 14: 
         Intent case14 = new Intent(MainActivity.this, Perguntas.class); 
         startActivity(case14); 
         break; 

       } 
      } 
     }); 
    } 

} 
+1

'String [] textoList [] = getResources()。getStringArray(R.array.itens);'從strings.xml中oncreate。注意你有'String [] textoList = r.getStringArray(R.array.itens);'。 'getResources(')需要一個上下文。一旦創建活動,上下文就可用。移動你的代碼在onCreate – Raghunandan

+0

什麼是錯誤 –

+0

「但我意識到我不應該在Java中創建一個列表,而是使用一個已經在strings.xml文件中創建的數組」 - 「String [] textoList'不是一個'List',你已經在使用直接從資源中獲取的一串字符串。 –

回答

1

創建一個如果不存在,則在app/src/main/res/values中稱爲array.xml。您可以添加字符串,像這樣:

<?xml version="1.0" encoding="utf-8"?> 
<resources> 
    <string-array name="itens"> 
     <item>Visto</item> 
     <item>Alojamento</item> 
     <!--Add your other words here--> 
    </string-array> 
</resources> 

,並且可以使用getResources().getStringArray(R.array.itens);Activity訪問它們。

1

試試這個:

String[] textoList; 

@Override 
public void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    setContentView(R.layout.inicio); 

    textoList = getResources().getStringArray(R.array.itens); 
} 

和你itens陣列strings.xml如下:

<?xml version="1.0" encoding="utf-8"?> 
<resources> 
    ............... 
    ...................... 
    <string-array name="itens"> 
     <item>Visto</item> 
     <item>Alojamento</item> 
     <item>C.P.F.</item> 
     <item>Alimentação</item> 
     <item>Carteirinha</item> 
     <item>Guia</item> 
     <item>Registro</item> 
     ................ 
     ....................... 
    </string-array> 
</resources> 

希望這將有助於〜

+0

如果我的答案看起來很有用,那麼你可以把它標記爲正確的答案並投票。提前致謝 :) – FAT