選擇除最上面一行以外的所有行

Question

如何返回除第一行以外的表中的所有行。這是我的sql語句：

Select Top(@TopWhat) * 
from tbl_SongsPlayed 
where Station = @Station 
order by DateTimePlayed DESC 

如何更改我的SQL語句以返回除第一行以外的所有行。

非常感謝

Answer 1

根據您的數據庫產品，您可以使用row_number()：

select * 
from 
(
    Select s.*, 
    row_number() over(order by DateTimePlayed DESC) rn 
    from tbl_SongsPlayed s 
    where s.Station = @Station 
) src 
where rn >1 

Answer 2

假設你有一個tbl_SongsPlayed一個唯一的ID，你可以做這樣的事情：

// Filter the songs first 
With SongsForStation 
As (
    Select * 
    From tbl_SongsPlayed 
    Where Station = @Station 
) 
// Get the songs 
Select * 
From SongsForStation 
Where SongPlayId <> (
    // Get the top song, most recently played, so you can exclude it. 
    Select Top 1 SongPlayId 
    From SongsForStation 
    Order By DateTimePlayed Desc 
    ) 
// Sort the rest of the songs. 
Order By 
    DateTimePlayed desc 
     Where 

Answer 3

SQL 2012還具有相當方便的OFFSET子句：

Select Top(@TopWhat) * 
from tbl_SongsPlayed 
where Station = @Station 
order by DateTimePlayed DESC 
OFFSET 1 ROWS 

Answer 4

已經'克里斯布'給了一個非常簡潔的答案。但你也可以試試這個...

的EXCEPT操作數（http://msdn.microsoft.com/en-us/library/ms188055.aspx）

Select Top(@TopWhat) * 
from tbl_SongsPlayed 
Except Select Top(1) * 
from tbl_SongsPlayed 
where Station = @Station 
order by DateTimePlayed DESC 

「不在」是可以使用的一個條款。