SQL Server從基於日期的表中獲取下一個前面的行

Question

我有以下SQL Server查詢，我試圖從給定的Id獲取下一行和上一行。除非有兩個/更多的日期是相同的，否則所有的工作都很好，那麼我的邏輯就會崩潰。

如果設置@currentId = 4那麼我回去ID 7的分組

（應該是ID 6）如果設置@currentId = 6，然後我回去ID 2（應該是ID 4 ）未來

declare @t table (i int, d datetime) 
insert into @t (i, d) 
select 1, '17-Nov-2009 07:22:13' union 
select 2, '18-Nov-2009 07:22:14' union 
select 3, '17-Nov-2009 07:23:15' union 
select 4, '20-Nov-2009 07:22:18' union 
select 5, '17-Nov-2009 07:22:17' union 
select 6, '20-Nov-2009 07:22:18' union 
select 7, '21-Nov-2009 07:22:19' 

--order that I want 
select * from @t order by d desc, i 

declare @currentId int; set @currentId = 4 

--Get Prev 
select TOP 1 * from @t where d > (select TOP 1 d from @t where i = @currentId order by d, i desc) order by d, i desc 

--Get Next 
select TOP 1 * from @t where d < (select TOP 1 d from @t where i = @currentId order by d desc) order by d desc 

誰能幫我解決如何保證獲得基於給定ID的下一個/上行時，請注意，重要的是，我把這個順序，日期說明，ID ASC

非常感謝

編輯：應當指出的是，這將被用於SQL Server 2005的

Answer 1

你幾乎在那裏...試試這個。有效地改變日期比較是「...-或-等於對」，並告訴它不匹配當前的ID，因此不會返回同一行...

declare @currID int 
set @currID = 4 

select top 1 * 
from (
    select * 
     from @t 
     where d = (select d from @t where i = @currID) 
      and i > @currID 
    union ALL 
    select * 
     from @t 
     where d < (select d from @t where i = @currID) 
) as t 
order by d desc, i 

select top 1 * 
from (
    select * 
     from @t 
     where d = (select d from @t where i = @currID) 
      and i < @currID 
    union ALL 
    select * 
     from @t 
     where d > (select d from @t where i = @currID) 
) as t 
order by d, i desc 

Answer 2

玩具可以嘗試這樣的事情

declare @t table (i int, d datetime) 
     insert into @t (i, d) 
     select 1, '17-Nov-2009 07:22:13' union 
     select 2, '18-Nov-2009 07:22:14' union 
     select 3, '17-Nov-2009 07:23:15' union 
     select 4, '20-Nov-2009 07:22:18' union 
     select 5, '17-Nov-2009 07:22:17' union 
     select 6, '20-Nov-2009 07:22:18' union 
     select 7, '21-Nov-2009 07:22:19' 

     --order that I want 
     select * from @t order by d desc, i 

     declare @currentId int; 
     set @currentId = 4 



SELECT TOP 1 t.* 
FROM @t t INNER JOIN 
      (
       SELECT d CurrentDateVal 
       FROM @t 
       WHERE i = @currentId 
      ) currentDate ON t.d <= currentDate.CurrentDateVal AND t.i != @currentId 
    ORDER BY t.d DESC 

    SELECT t.* 
FROM @t t INNER JOIN 
      (
       SELECT d CurrentDateVal 
       FROM @t 
       WHERE i = @currentId 
      ) currentDate ON t.d >= currentDate.CurrentDateVal AND t.i != @currentId 
    ORDER BY t.d 

你一定要小心，它可以看起來應該6既是prev又是next。