語法錯誤（缺少操作員）在查詢表達式 - MS-訪問

這不會產生語法錯誤，但它給出錯誤的參數錯誤：語法錯誤（缺少操作員）在查詢表達式 - MS-訪問

SELECT left(
    [aname], 
IIF(instr([aname], " ") = 0 AND instr([aname], ",") = 0, 
    Len(FinalForgotten.aname), 
    IIF(instr([aname], ",") = 0, 
    InStr(1,[aname]," ")-1, 
    InStr(1,[aname],",")-1))) 
& "," & 

right(
    [aname], 
IIF(instr([aname], " " = 0 AND instr([aname], ",") = 0, 
    Len(FinalForgotten.aname), 
    IIF(instr([aname], ",") = 0, 
     Len(aname)-InStr(1,[aname]," "), 
     Len(aname)-InStr(1,[aname],","))))) 
& " " & 

defense_final.middle_initial AS fullname INTO FinalForgottenWithMiddle 
FROM FinalForgotten INNER JOIN defense_final ON (right(FinalForgotten.aname, 
IIF(instr([aname], ",") = 0, 
Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname]," "), 
Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname],",") 
) 
)=defense_final.first_name) AND (left(FinalForgotten.aname, 
IIF(instr([aname], ",") = 0, 
    InStr(1,FinalForgotten.[aname]," ")-1, 
    InStr(1,FinalForgotten.[aname],",")-1 
    ) 
)=defense_final.last_name);

因此增加額外的參數我現在得到語法錯誤「失蹤），]或查詢表達式中的項目「：

SELECT left(
    [aname], 
IIF(instr([aname], " ") = 0 AND instr([aname], ",") = 0, 
    Len(FinalForgotten.aname), 
    IIF(instr([aname], ",") = 0, 
    InStr(1,[aname]," ")-1, 
    InStr(1,[aname],",")-1))) 
& "," & 

right(
    [aname], 
IIF(instr([aname], " ") = 0 AND instr([aname], ",") = 0, 
    Len(FinalForgotten.aname), 
    IIF(instr([aname], ",") = 0, 
     Len(aname)-InStr(1,[aname]," "), 
     Len(aname)-InStr(1,[aname],",")))) 
& " " & 

defense_final.middle_initial AS fullname INTO FinalForgottenWithMiddle 
FROM FinalForgotten INNER JOIN defense_final ON 

left(FinalForgotten.aname, 
    IIF(instr([aname], " ") = 0 AND instr([aname], ",") = 0, 
     Len(FinalForgotten.aname), 
     IIF(instr([aname], ",") = 0, 
     InStr(1,FinalForgotten.[aname]," ")-1, 
     InStr(1,FinalForgotten.[aname],",")-1))) 

=defense_final.last_name AND 

right(FinalForgotten.aname, 
     IIF(instr([aname], " ") = 0 AND instr([aname], ",") = 0, 
     Len(FinalForgotten.aname), 
     IIF(instr([aname], ",") = 0, 
     Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname]," "), 
     Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname],",")))) 

=defense_final.first_name;

任何解決方法？

感謝您的回覆。

來源

2010-12-19 JohnMerlino

may I s你最好給你的表一個簡短的（1個字母）別名，並更新你的問題？這會讓我覺得它更具可讀性。 – 2010-12-20 14:41:55

你提到「錯誤的參數錯誤」。你能指定錯誤嗎？通常情況下，當字段拼寫錯誤時。 – 2010-12-20 14:47:20

@iDevlop它說：「在查詢表達式中使用的函數參數的錯誤數量」左（...「 – JohnMerlino 2010-12-20 15:08:30

它會更容易把這種邏輯到VBA功能，使您的查詢看起來像這樣

SELECT GetFullNameWithMiddle([aname]) AS fullname 
INTO FinalForgottenWithMiddle 
FROM FinalForgotten INNER JOIN defense_final 
    ON GetLastName([aname])=defense_final.last_name 
    AND GetFirstName([aname])=defense_final.first_name

由於你說你不想使用VBA，試試這個。我封閉每

InStr(x, y) = 0

括號

，所以

IIf(InStr(x, y) = 0 AND InStr(p, q) = 0, g, h)

成爲

IIf((InStr(x, y) = 0) AND (InStr(p, q) = 0), g, h)

做出這樣的轉變讓我切換到查詢設計網格，這意味着SQL解析器喜歡它：

SELECT left(
    [aname], 
    IIF((instr([aname], " ") = 0) AND (instr([aname], ",") = 0), 
    Len(FinalForgotten.aname), 
    IIF((instr([aname], ",") = 0), 
    InStr(1,[aname]," ")-1, 
    InStr(1,[aname],",")-1))) 

    & "," & 

right(
    [aname], 
    IIF((instr([aname], " ") = 0) AND (instr([aname], ",") = 0), 
    Len(FinalForgotten.aname), 
    IIF((instr([aname], ",") = 0), 
     Len(aname)-InStr(1,[aname]," "), 
     Len(aname)-InStr(1,[aname],",")))) 

    & " " & 

defense_final.middle_initial AS fullname INTO FinalForgottenWithMiddle 
FROM FinalForgotten INNER JOIN defense_final ON 

left(FinalForgotten.aname, 
    IIF((instr([aname], " ") = 0) AND (instr([aname], ",") = 0), 
    Len(FinalForgotten.aname), 
    IIF((instr([aname], ",") = 0), 
    InStr(1,FinalForgotten.[aname]," ")-1, 
    InStr(1,FinalForgotten.[aname],",")-1))) 

=defense_final.last_name AND 

right(FinalForgotten.aname, 
    IIF((instr([aname], " ") = 0) AND (instr([aname], ",") = 0), 
    Len(FinalForgotten.aname), 
    IIF((instr([aname], ",") = 0), 
    Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname]," "), 
    Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname],",")))) 

=defense_final.first_name;

來源

2010-12-20 18:59:58 phoog

不適合我。我不太擅長VB。我希望堅持與SQL。 – JohnMerlino 2010-12-20 23:19:13

VBA環境在告訴你語法錯誤在哪裏做得更好。而VBA做你在這裏做的事情要比你構建的SQL語句簡單得多。但每一個都是他自己的。如果我必須用SQL來做，那麼我會使用LIKE而不是InStr（'[aname] LIKE「* *」'會得到與InStr（[aname]，「」）> 0'）相同的結果。我在編輯時查詢了一下你的查詢，我想你可能只需要確保你到處都有括號。查看新編輯的答案以獲取建議。 – phoog 2010-12-20 23:41:42

線10

right(

沒有相應的右括號

來源

2010-12-20 00:41:22 Odin

感謝您的回覆，但我添加了一個右括號，但然後得到一個語法錯誤，指出」Missing「，]或Item in查詢表達式「並將光標置於第一個AND上。 – JohnMerlino 2010-12-20 02:28:02

SELECT left([aname], 所以[aname]是一個文本字段。

IIF(instr([aname], " ") = 0 AND instr([aname], ",") = 0,

如果這個條件爲真，你想向左字符串的長度爲：

FinalForgotten.aname,

這是不是一個整數。你想：

SELECT left(
    [aname], 
IIF(instr([aname], " ") = 0 AND instr([aname], ",") = 0, 
    Len(FinalForgotten.aname),

來源

2010-12-20 02:42:46 JeffO

這是測試？對我來說，它仍然會有同樣的錯誤。 – JohnMerlino 2010-12-20 13:36:57

IIF(instr([aname], " " = 0 AND instr([aname], ",") = 0,

第12行應該是

IIF(instr([aname], " ") = 0 AND instr([aname], ",") = 0,

來源

2010-12-20 16:01:19

它仍然給出錯誤「Missing」，]或Item中的查詢表達式「 – JohnMerlino 2010-12-20 16:21:59

語法錯誤（缺少操作員）在查詢表達式 - MS-訪問

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