無法在下拉框中發佈從db中選擇的值

Question

我花了一些時間試圖讓下拉框正常工作，從數據庫中獲取部門和位置的值。這工作正常，我添加了額外的日期字段，因此客戶可以選擇特定時期，地點和部門的記錄。當我執行運行departmentReport.php的表單時，即使試圖回顯每個值，頁面也會返回空白，如下所示。

<form id="departmentReport" action="departmentReport.php" method="get" onsubmit="#"> 
     <fieldset id="departmentReport"> 
      <h3>Department Report</h3> 
      <br> 
      <?php 
      include 'includes/DbCon.php'; 
     $sql = "select department_name from departments"; 

      echo"<select name = 'departments' value=''>Department Name</option>"; 

      foreach ($conn->query($sql) as $row){ 
       echo "<option value=$row[department_name]>$row[department_name]</option>";} 
      echo "</select>"; 

      ?> 
      <br></br> 
    <?php 
      include 'includes/DbCon.php'; 
     $sql = "select `location_name` from `location`"; 

      echo "<select name = 'location' value=''>Location Name</option>"; 

      foreach ($conn->query($sql) as $row){ 
       echo "<option value=$row[location_name]>$row[location_name]</option>";} 
      echo "</select>"; 

      ?> 
      <br></br><br> 
       <label for="date">Date From<br></label> 
       <input id="date1" type="date" name="dateF" 
         autofocus="true"/> 
      <br> 
      <br> 
       <label for="date">Date To<br></label> 
       <input id="date2" type="date" name="date2" 
         autofocus="true"/> 
      <br> 
      <br> 
      <input type="submit" class="button" value="Submit"> 

在提交departmentReport.php被付諸行動

<?php 


include "../includes/dbCon.php"; //* CONNECTION TO DATABASE 

$department = mysqli_real_escape_string($conn, $_POST['departments']); //* CLEAN DATA, THIS DELETES ANY SPECIAL CHARACTERS THAT CAN BE USED FOR MALICIOUS CODE 
$location = mysqli_real_escape_string($conn, $_POST['location']); //* CLEAN DATA, THIS DELETES ANY SPECIAL CHARACTERS THAT CAN BE USED FOR MALICIOUS CODE 
$date1 = mysqli_real_escape_string($conn, $_POST['date1']); //* CLEAN DATA, THIS DELETES ANY SPECIAL CHARACTERS THAT CAN BE USED FOR MALICIOUS CODE 
$date2 = mysqli_real_escape_string($conn, $_POST['date2']); //* CLEAN DATA, THIS DELETES ANY SPECIAL CHARACTERS THAT CAN BE USED FOR MALICIOUS CODE 

echo "$department"; 
echo "$location"; 
echo "$date1"; 
echo "$date2"; 

這帶來下面的結果..

但是調整後什麼時候能得到我見我選擇的值爲 http://localhost:8888/departmentReport.php?departments=Marketing&location=London&dateFrom=02%2F01%2F2017

我不確定爲什麼我看不到值時回聲！

任何援助將不勝感激。

Answer 1

您檢索發佈數據時，變量是錯誤的

選擇部門的html代碼：

<select name = departments value=''>Department Name</option> 

在選擇的形式，名稱是「部門」，但是當你在PHP中檢索它們，它是：

$_POST['departmant_name'] 

這是錯誤的輸入變量名稱。它應該是：

$_POST['departments'] 

另外，請把報價上的選擇名稱

<select name = 'departments' value=''>Department Name</option> 

所有其他變量也是錯誤的標記。

看起來像你輸入數據庫列名稱，而不是表單輸入名稱。

編輯： 我也注意到，在您的表單，表單「方法」設置爲「GET」，而你的PHP代碼是使用「POST」