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返回一個toString這是我的課:從一個StringBuffer
public String toString(){
status = status1.getStat();
item = status1.getItem();
boolean checked;
checked = false;
StringBuffer sb1 = new StringBuffer("");
StringBuffer s1, s2, s3, z;
s1 = new StringBuffer(item1[1]+"["+item2[1]+"] ");
s2 = new StringBuffer(item1[2]+"["+item2[2]+"] ");
s3 = new StringBuffer(item1[3]+"["+item2[3]+"] ");
z = new StringBuffer(" player("+player+") - "+points+" points ");
//sb1.append(item1[1]+"["+item2[1]+"] "+item1[2]+"["+item2[2]+"] "+ item1[3]+"["+item2[3]+"] "+ "player("+player+") - "+points+" points ");
if (status == 1 && item.equals(item1[1])){
item1[1] = "*";
s1 = sb1.append(item1[1]+" ");
//sb1.delete(1,4);
}else if (status == 1 && item.equals(item1[2])){
item1[2] = "*";
s2 = sb1.append(item1[2]+" ");
}else if(status == 1 && item.equals(item1[3])){
item1[3] = "*";
s3 = sb1.append(item1[3]+" ");
}
return s1.toString()+s2.toString()+s3.toString()+z.toString();
我的輸出如下:
Let:
item1[1] = Alpha
item2[1] = 1
item3[1] = 0
-----
item1[2] = Beta
item2[2] = 1
item2[2] = 0
-----
item1[3] = Charlie
item2[3] = 2
我的輸出是:
when status = 1 and item = item1[1]
--
* Beta[1] Charlie[2]
--
When run the code for the second time
*[1] * Charlie[2]
--
When i run the code for the third time
*[1] *[1] Charlie[2]
是否有可能使它如下所示?
when status = 1 and item = item1[1]
--
* Beta[1] Charlie[2]
--
When run the code for the second time
* * Charlie[2]
--
When i run the code for the third time
* * *
這將需要以隨機順序發生。
我不明白。你想每次調用同一個對象時'toString()'返回不同的值嗎? – 2011-04-29 03:09:59
是的,如果條件滿足,我希望它將item1重命名爲*並移除項目2周圍的[] – ART 2011-04-29 03:11:23