以及傢伙,我這裏有一個小問題,我有3個集裝箱,並與n個節點的XML ...我想放在容器中,XML的任何值,該值不能是一箇舊值和容器不應該具有相同的值...我在AS3這個代碼,但它不工作:S換弦
package
{
import flash.display.MovieClip;
import flash.display.Sprite;
import flash.events.Event;
import flash.events.MouseEvent;
import flash.text.TextField;
public class Pruebas extends Sprite
{
public var arr:Array = new Array("valor0","valor1","valor2","valor3","valor4","valor5")
public var str1:String=arr[0];
public var str2:String=arr[1];
public var str3:String=arr[2];
public var te1:TextField = new TextField();
public var te2 :TextField = new TextField();
public var te3 :TextField = new TextField();
public var btn :MovieClip = new MovieClip();
public function Pruebas()
{
te1.text = str1;
te2.text = str2;
te3.text = str3;
addChild(te1);
addChild(te2);
addChild(te3);
te2.x = 50;te3.x=100;
btn.graphics.beginFill(0xff00ff);
btn.graphics.drawCircle(151,150,15);
addChild(btn);
btn.addEventListener(MouseEvent.CLICK,cambiar);
}
public function cambiar(e:Event):void{
var minLimit:uint = 0;
var maxLimit:uint = arr.length-1;
var range:uint = maxLimit - minLimit;
var someNum:Number = Math.ceil(Math.random()*range) + minLimit;
if(str1 == arr[someNum]){
while(str1 == arr[someNum]){
someNum = Math.ceil(Math.random()*range) + minLimit;
}
str1 = arr[someNum];
}else{
str1 = arr[someNum];
}
someNum= Math.ceil(Math.random()*range) + minLimit;
if(str2 == arr[someNum]){
while(str2 == arr[someNum]){
someNum = Math.ceil(Math.random()*range) + minLimit;
}
str2 = arr[someNum];
}else{
str2 = arr[someNum];
}
someNum= Math.ceil(Math.random()*range) + minLimit;
if(str3 == arr[someNum]){
while(str3 == arr[someNum] || str3 ==str1 || str3 == str2){
someNum = Math.ceil(Math.random()*range) + minLimit;
}
str3 = arr[someNum];
}else{
str3 = arr[someNum];
}
te1.text = str1;
te2.text = str2;
te3.text = str3;
}
}
}
愛德華檢查這個代碼,這個代碼我做
if(imgactual == myXML.internas.item[someNum][email protected]){
while(imgactual == myXML.internas.item[someNum][email protected]){
someNum = Math.ceil(Math.random()*range) + minLimit;
}
imgactual = myXML.internas.item[someNum][email protected]
}else{
imgactual = myXML.internas.item[someNum][email protected]
}
someNum= Math.ceil(Math.random()*range) + minLimit;
if((imgpostactual == myXML.internas.item[someNum][email protected]) || (imgpostactual == imgactual)){
while(imgpostactual == myXML.internas.item[someNum][email protected] || imgpostactual == imgactual){
someNum = Math.ceil(Math.random()*range) + minLimit;
}
imgpostactual = myXML.internas.item[someNum][email protected]
}else{
imgpostactual = myXML.internas.item[someNum][email protected]
}
someNum= Math.ceil(Math.random()*range) + minLimit;
if((imgpreactual == myXML.internas.item[someNum][email protected]) || (imgpostactual == imgpreactual) || (imgpreactual == imgactual)){
while((imgpreactual == myXML.internas.item[someNum][email protected]) || (imgpostactual == imgpreactual) || (imgpreactual == imgactual)){
someNum = Math.ceil(Math.random()*range) + minLimit;
}
imgpreactual = myXML.internas.item[someNum][email protected];
}else{
imgpreactual = myXML.internas.item[someNum][email protected];
}
trace(imgactual);
trace(imgpreactual);
trace(imgpostactual);
這段代碼的壞處是總是循環而t碟剎很長一段時間:S和我認爲它不工作:S
嗯OKü洗牌陣列的位置是確定......但在其他的循環?想象一下,每1分鐘更換一次,每次都必須在數組中有不同的值:S每當他們改變時,都是我的問題總是有人與其他人相等:S – 2012-02-26 16:38:34
您可以重新洗牌,也可以將數組中的以下3個元素。 – Eduardo 2012-02-26 16:55:18
你在我的代碼中看起來有什麼錯誤嗎?語法或邏輯我不知道或爲你我的代碼工作? – 2012-02-27 20:43:00