獲取Facebook用戶性別使用臉譜圖api

Question

我做了一個代碼，以顯示用戶的朋友和朋友的名稱，身份證和個人資料圖片。問題是要獲得朋友的性別，並將代碼放在第一個代碼下面，但它似乎不起作用，但它在獲取我的性別信息的情況下起作用。

function displayUsersIcons($criteria) { 
$users = $criteria['users']; 
$nb_display = $criteria['nb_display']; 
$width = $criteria['width']; 
echo 'data'.$gen = $criteria['gen']; 


if($width=='') $width="200"; 

if($nb_display>count($users) || $nb_display=='') $nb_display=count($users); //display value never bigger than nb users 

$display = ''; 
for($i=0;$i<$nb_display;$i++) { 

    $name = $users[$i]['name']; 
    $picture = $users[$i]['picture']; 
    $url = $users[$i]['url']; 
    $user_id = $users[$i]['id']; 
    $cookie = self::$cookie; 
    if($cookie['access_token']!='') { 
    $url = 'https://graph.facebook.com/'.$name.'?access_token='.$cookie['access_token']; 
    //echo '<a href="'.$url.'" target="_blank">'.$url.'</a><br>'; 
    $data = json_decode($this->getDataFromUrl($url)); 

    $fb['gender'] = $data->gender; 

    $gender=$fb; 



     $display .= '<li class="mispan main-span" gen="'.$gender.'" data="'.$user_id.'" unme="'.$name.'" upic="'.$picture.'">'; 
     $display .= '<div class="thumbnail">'; 
     $display .= '<h3 class="miheader">'.$name.'</h3>'; 
    $display .= '<a href="'.$url.'" target="_blank" title="'.$name.'">'; 
    $display .= '<div class="miprofile-pic-cnt" style="background-image:url('.$picture.')" ></div>'; 
    $display .= '</a>'; 
    $display .= '<div class="caption" style="text-align:center;">'; 
    $display .= '<p><a href="#" class="btn kssico miclickks"><img src="Iconos/lips.png" /></a> <a href="#" class="btn bdico miclickbd"><img src="Iconos/bed.png" /></a></p>'; 
    $display .= '</div>'; 
    $display .= '</div>'; 
    $display .= '</li>';    



} 
return $display; 

}

代碼即可獲得朋友的性別

$cookie = self::$cookie; 
if($cookie['access_token']!='') { 
$url = 'https://graph.facebook.com/'.$name.'?access_token='.$cookie['access_token']; 
//echo '<a href="'.$url.'" target="_blank">'.$url.'</a><br>'; 
$data = json_decode($this->getDataFromUrl($url)); 

$fb['gender'] = $data->gender; 

$gender=$fb; 

Answer 1

http://graph.facebook.com/<facebook_id>?fields=gender 

fields=gender爲您提供了在給定的Facebook ID性別。