選擇具有獨特和聯盟統計所有

-1

SELECT COUNT(DISTINCT `ID`) FROM db1.table UNION ALL SELECT COUNT(DISTINCT `ID`) FROM db2.table

我真正的查詢更復雜的是，我已經離開JOIN和多重條件等..

該查詢返回我有2個結果的數組：Count 1和Count 2

我怎樣才能返回一個結果？ Count 1 + Count 2？

謝謝！

來源

2015-10-14 Clément Andraud

試試這個：

SELECT (SELECT COUNT(DISTINCT `ID`) FROM db1.table) + 
     (SELECT COUNT(DISTINCT `ID`) FROM db2.table)

如果你也想返回單獨db1，db2計數，然後使用該查詢：

SELECT countDb1, countDb2, countDb1 + countDb2 AS total 
FROM (
SELECT (SELECT COUNT(DISTINCT `ID`) FROM db1.table) AS countDb1, 
     (SELECT COUNT(DISTINCT `ID`) FROM db2.table) AS countDb2) AS t

來源

2015-10-14 16:00:07

選擇具有獨特和聯盟統計所有

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