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我使用的是PHP4服務器如何使php5 xmlParser在php4服務器上工作?
<?xml version="1.0" encoding="UTF-8" ?>
<events>
<record>
<event>ticket</event>
<eventDate>09/12/2010</eventDate>
<desc>http://asce.co.il/page.asp?page_parent=611</desc>
</record>
</events>
這個XML和我有這個解析器能夠對XML文件
<?php
header("Content-type: text/html; charset=utf-8");
$record = array(
'event' => $_POST['event'],
'eventDate' => $_POST['eventDate'],
'desc' => $_POST['desc'],
);
$doc = new DOMDocument();
$doc->load('calendar.xml');
$doc->formatOutput = true;
$r = $doc->getElementsByTagName("events")->item(0);
$b = $doc->createElement("record");
$event = $doc->createElement("event");
$event->appendChild(
$doc->createTextNode($record["event"])
);
$b->appendChild($event);
$eventDate = $doc->createElement("eventDate");
$eventDate->appendChild(
$doc->createTextNode($record["eventDate"])
);
$b->appendChild($eventDate);
$desc = $doc->createElement("desc");
$desc->appendChild(
$doc->createTextNode($record["desc"])
);
$b->appendChild($desc);
$r->insertBefore($b,$r->firstChild);
$doc->save("calendar.xml");
header("Location: {$_SERVER['HTTP_REFERER']}");
?>
寫這一切都在PHP5工作的偉大服務器,但我的問題是,我的服務器只有php4支持
我需要在腳本中更改哪些內容才能在我的服務器上使用它? 謝謝你們!
謝謝理查! – Ofear 2011-01-10 09:19:33