我有一個列表視圖的酒店,我想當用戶點擊一個項目長按一個對話框出現與點擊酒店信息從SQLite數據庫檢索(位置,地址,電話數...等)。 我從列表中的數據庫檢索數據。 在將列表轉換爲toString()時的對話框消息中,結果有多餘的方括號,例如:Phone:[02239348],我應該怎麼做?有另一種方法嗎?與SQLite數據庫中的數據對話框
下面是從DataSource.java代碼來檢索數據庫,從位置:
public List<Hotel> getHotelLocation(String hotelName) {
List<Hotel> hotels = new ArrayList<Hotel>();
Cursor cursor = database.query(MySQLiteHelper.TABLE_Hotel,
hotelsLoc, hotelsNames[0] + " like " + "'" + hotelName + "'", null, null, null, null);
cursor.moveToFirst();
while (!cursor.isAfterLast()) {
Hotel hotel = cursorToHotel(cursor);
hotels.add(hotel);
cursor.moveToNext();
}
// Make sure to close the cursor
cursor.close();
return hotels;
}
private Hotel cursorToHotel(Cursor cursor) {
// TODO Auto-generated method stub
Hotel hotelname = new Hotel();
hotelname.setName(cursor.getString(0));
return hotelname;
}
這裏是警告對話框:
public boolean onItemLongClick(AdapterView<?> parent, View view, int position,
long id) {
// TODO Auto-generated method stub
String hotelName = (String) ((TextView)parent.getChildAt(position)).getText();
List<Hotel> location = datasource.getHotelLocation(hotelName);
String loc = "Location: " + location.toString();
List<Hotel> address = datasource.getHotelAddress(hotelName);
String add = "Address: " + address.toString();
List<Hotel> rating = datasource.getHotelRating(hotelName);
String rat = "Rating: " + rating.toString();
List<Hotel> phone = datasource.getHotelPhone(hotelName);
String phoneN = "Phone: " + phone.toString();
AlertDialog.Builder builder = new AlertDialog.Builder(this);
builder.setTitle("Information about " + hotelName);
builder.setMessage(loc + "\n" + add + "\n" + rat + "\n" + phoneN + "\n");
builder.setCancelable(true);
builder.show();
return false;
}
能否請您修改我的密碼?我不知道要修改哪些部分 – MahaK 2012-04-24 20:42:51
您可以發佈酒店類的來源嗎?我想看看getHotelPhone方法的功能。 – twaddington 2012-04-24 20:44:31
public列表 getHotelPhone(String hotelName){ \t \t列表 hotels = new ArrayList (); \t \t光標光標= database.query(MySQLiteHelper.TABLE_Hotel, \t \t \t \t hotelsPhone,hotelsNames [0] + 「喜歡」 + 「 '」 + hotelName + 「'」,NULL,NULL,NULL,NULL); \t \t cursor.moveToFirst(); \t \t而{ \t \t \t酒店賓館= cursorToHotel(光標)(cursor.isAfterLast()!); \t \t \t hotels.add(hotel); \t \t \t cursor.moveToNext(); \t \t} \t \t //確保關閉遊標 \t \t cursor.close(); \t \t返回酒店; \t} –
MahaK
2012-04-24 20:45:48