循環問題 - UIMA魯塔

Question

目的：

要分配的標題級別。

第一個標題是分配的級別1.我提取字體系列和它的大小，尋找匹配的標題。一旦級別被分配，我取消標題的標題，在另一個註釋（HeadingHierarchy）中保留標題&。等級完成後，只要Headinglevel註釋中剩下任何標題，就會一次又一次調用同一個塊。

問題：

該腳本工作正常，發現所有1級標題。但是，當通過Call語句執行該塊時，它僅找到每個級別的第一個匹配（級別2以上）。因此電平爲低於輸入的總數變爲10，而它必須是4。

輸入：（.txt）的

Apache UIMA Ruta Overview =>Arial,18 
What is Apache UIMA Ruta? =>Arial,16 
Getting started =>Arial,16 
UIMA Analysis Engines =>Arial,16 
Ruta Engine =>Times New Roman,14 
Configuration Parameters =>Arial,10 
Annotation Writer =>Times New Roman,14 
Configuration Parameters =>Arial,10 
Apache UIMA Ruta Language =>Arial,18 
Syntax =>Arial,16 
Rule elements and their matching order =>Arial,16 

腳本：

PACKAGE uima.ruta.example; 

DECLARE Headinglevel(STRING family, INT size, INT level); 
DECLARE HeadingHierarchy(STRING family, INT size, INT level); 
DECLARE FontFamily, FontSize; 

STRING family; 
INT size; 

RETAINTYPE(BREAK); 
    BREAK? #{-PARTOF(Headinglevel)} @SPECIAL+ W+ COMMA NUM{->MARK(Headinglevel,2,6), MARK(HeadingHierarchy,2,6), MARK(FontFamily,4), MARK(FontSize,6)}; 
RETAINTYPE; 

h:Headinglevel{->h.family = family, HeadingHierarchy.family = family} 
<-{FontFamily{PARSE(family)};}; 

h:Headinglevel{->h.size = size, HeadingHierarchy.size = size} 
<-{FontSize{PARSE(size)};}; 

INT i=1; 

BLOCK(ForEachHeadLevel)Document{} 
{ 
    # h:Headinglevel{-> family = h.family, size = h.size}; 
    h:Headinglevel{AND(h.family == family, h.size == size)-> h.level=i, HeadingHierarchy.level = i, UNMARK(h)}; 
} 
Headinglevel{->i=i+1, CALL(Test2.ForEachHeadLevel)}; 
Document{->LOG(" LEVELS : " + (i))}; 

預計產量：

HeadingHierarchy      Feature 

Apache UIMA... =>Arial,18     level: 1 
What is Apa... =>Arial,16     level: 2 
Getting sta... =>Arial,16     level: 2 
UIMA Analys... =>Arial,16     level: 2 
Ruta Engine... =>Times New Roman,14  level: 3 
Configurati... =>Arial,10     level: 4 
Annotation ... =>Times New Roman,14  level: 3 
Configurati... =>Arial,10     level: 4 
Apache UIMA... =>Arial,18     level: 1 
Syntax =>Ar... =>Arial,16     level: 2 
Rule elemen... =>Arial,16     level: 2 

Answer 1

問題是CALL限制了規則元素匹配的跨度上的窗口。這意味着BLOCK僅在現有的Headinglevel註釋中執行。但是，您需要擁有完整的文檔，以便塊中的第二條規則完成其工作。

這是最有可能不是最好的解決辦法，但來到了我的腦海裏的第一個。

你可以在塊內無論CALL行動的限制與DOCUMENTBLOCK重置窗口完整的文檔：

BLOCK (ForEachHeadLevel)Document{} 
{ 
    DOCUMENTBLOCK Document{} 
    { 
     # h:Headinglevel{-> family = h.family, size = h.size}; 
     h:Headinglevel{AND(h.family == family, h.size == size)-> h.level=i, HeadingHierarchy.level = i, UNMARK(h)}; 
    } 
} 

DOCUMENTBLOCK是塊擴展。您需要在additionalExtensions配置參數中包含org.apache.uima.ruta.block.DocumentBlockExtension。

下面是使用foreach塊的其他的解決方案：

INT i=0; 
FOREACH(hl) Headinglevel{}{ 
    hl{IS(Headinglevel)-> i=i+1, family = hl.family, size = hl.size}; 
    h:Headinglevel{h.family == family, h.size == size -> h.level=i, HeadingHierarchy.level = i, UNMARK(h)}; 
} 

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