屬性文件

Question

List<PData> listproperties = new ArrayList<PData>(); 
     try 
     { 
     PData PData = new PData(); 
     Properties properties = new Properties(); 
     File file = new File("src/Config/object.properties"); 
     FileInputStream Inputpropertyfile = new FileInputStream(file); 
     properties.load(Inputpropertyfile); 
     Inputpropertyfile.close(); 
     @SuppressWarnings("rawtypes") 
     Enumeration Keys = properties.keys(); 
     while(Keys.hasMoreElements()) 
     { 
      String key = (String) Keys.nextElement();//Getting Key from property file. 
       String Value = properties.getProperty(key);}} 

嗨的無序輸出，我是新來的Java我試圖導入具有巨大的設置鍵值對的屬性文件，在上面的代碼我能夠導入數據，但數據的輸入是非常無序的方式，我想在從上至下獲取數據，這樣我可以在其他類使用它的一些功能，

謝謝

Answer 1

這是不可能的使用java.util.Properties。你要麼需要一個定製的解析器，不同的文件格式，或者您需要把一些排序前綴鍵（001.key1=value，002.key2=value等），然後創建一個new TreeMap<>(properties)和遍歷它來代替。

Answer 2

使用下面的代碼來維持秩序

import java.util.*; 
import java.io.*; 

/** 
* Ordered properties implementation 
*/ 

public class LinkedProperties extends Properties{ 
    private static final long serialVersionUID = 1L; 

    private Map<Object, Object> linkMap = new LinkedHashMap<Object,Object>(); 

    public void clear(){ 
     linkMap.clear(); 
    } 
    public boolean contains(Object value){ 
     return linkMap.containsValue(value); 
    } 
    public boolean containsKey(Object key){ 
     return linkMap.containsKey(key); 
    } 
    public boolean containsValue(Object value){ 
     return linkMap.containsValue(value); 
    } 
    public Enumeration elements(){ 
     throw new RuntimeException("Method elements is not supported in LinkedProperties class"); 
    } 
    public Set entrySet(){ 
     return linkMap.entrySet(); 
    } 
    public boolean equals(Object o){ 
     return linkMap.equals(o); 
    } 
    public Object get(Object key){ 
     return linkMap.get(key); 
    } 
    public String getProperty(String key) { 
     Object oval = get(key); //here the class Properties uses super.get() 
     if(oval==null)return null; 
     return (oval instanceof String) ? (String)oval : null; //behavior of standard properties 
    } 
    public boolean isEmpty(){ 
     return linkMap.isEmpty(); 
    } 
    public Enumeration keys(){ 
     Set keys=linkMap.keySet(); 
     return Collections.enumeration(keys); 
    } 
    public Set keySet(){ 
     return linkMap.keySet(); 
    } 
    public void list(PrintStream out) { 
     this.list(new PrintWriter(out,true)); 
    } 
    public void list(PrintWriter out) { 
     out.println("-- listing properties --"); 
     for (Map.Entry e : (Set<Map.Entry>)this.entrySet()){ 
      String key = (String)e.getKey(); 
      String val = (String)e.getValue(); 
      if (val.length() > 40) { 
       val = val.substring(0, 37) + "..."; 
      } 
      out.println(key + "=" + val); 
     } 
    } 

    public Object put(Object key, Object value){ 
     return linkMap.put(key, value); 
    } 
    public int size(){ 
     return linkMap.size(); 
    } 
    public Collection values(){ 
     return linkMap.values(); 
    } 

    //for test purpose only 
    public static void main(String[] arg)throws Exception{ 
     Properties p0=new Properties(); 
     Properties p1=new LinkedProperties(); 
     p0.put("aaa","111"); 
     p0.put("bbb","222"); 
     p0.put("ccc","333"); 
     p0.put("ddd","444"); 

     p1.put("aaa","111"); 
     p1.put("bbb","222"); 
     p1.put("ccc","333"); 
     p1.put("ddd","444"); 

     System.out.println("\n--"+p0.getClass()); 
     p0.list(System.out); 
     p0.store(System.out,"comments"); 
     p0.storeToXML(System.out,"comments"); 
     System.out.println(p0.toString()); 

     System.out.println("\n--"+p1.getClass()); 
     p1.list(System.out); 
     p1.store(System.out,"comments"); 
     p1.storeToXML(System.out,"comments"); 
     System.out.println(p1.toString()); 
    } 
} 

Answer 3

謝謝大家，我得到的在這裏分享它一個明確的解決方案和思路，使每個人都可以利用

Enumeration Keys = properties.keys(); 
     List<String> list = Collections.list(Keys); 
     Collections.sort(list); 
     System.out.println(list); 
     Iterator<String> rows = list.iterator(); 

使用集合我得到所有的按鍵和將其存儲在列表和排序的整個數據，我從我的屬性文件