將文本數據轉換爲Json格式

我的文本數據轉換成JSON格式

這裏是從下面的表結構中提取的樣本的文本數據：

Metric - Column 1 , 
Design Project - Column 2 , 
Design Target* - Column 3 , 
Median Property* - Column 4 

Metric Design Project Design Target* Median Property* 
Source EUI (kBtu/ft²) 3.1 Not Available 127.9 
Site EUI (kBtu/ft²) 1.0 Not Available 40.7 
Source Energy Use (kBtu) 314.0 Not Available 12,793.0 
Site Energy Use (kBtu) 100.0 Not Available 4,074.2 
Energy Cost ($) 2,000.00 Not Available 81,484.00 
Total GHG Emissions (Metric Tons CO2e) 0.0 Not Available 0.5 
ENERGY STAR score (1-100) Not Available 75 50

這裏是代碼如下：

import csv 
import json 

with open('output.txt', 'r') as csvfile: # Opens file 
    filereader = csv.reader(csvfile, delimiter=' ') 
    i = 0 
    header = [] 
    out_data = [] 
    for row in filereader: 
     row = [elem for elem in row if elem] 
     if i == 0: 
      i+=2 
      row[1:3] = [row[1]+" "+row[2]] # Design Project key 
      row[2:4] = [row[2]+" "+row[3]] # Design Target key 
      row[3:5] = [row[3]+" "+row[4]] # Median Property* 
      header = row 
     else: 
      row[0:3] = [row[0]+" "+row[1]+" "+row[2]] # Metric 
      if len(row) == 5: # check conditions for better parse 
       row[1:2] = [row[1]] # Design Project value 
       row[2:4] = [row[2]+" "+row[3]] # Design Target 

      _dict = {} 
      for elem, header_elem in zip(row, header): 
       _dict[header_elem] = elem 
      out_data.append(_dict) 

    print json.dumps(out_data)

以上代碼正確處理前兩行數據。

這裏是代碼的輸出，

[{"Metric": "Source EUI (kBtu/ft\u00b2)", "Design Target*": "Not Available", "Median Property*": "127.9", "Design Project": "3.1"}, {"Metric": "Site EUI (kBtu/ft\u00b2)", "Design Target*": "Not Available", "Median Property*": "40.7", "Design Project": "1.0"}]

我怎樣才能讓完整的數據轉換成JSON格式？

來源

2017-10-17 venkat

您的數據並不一致。並且'row = [elem for elem in row if elem]'對於第三數據行將具有不同數量的元素，而對於第二數據行將具有不同數量的元素。這就是爲什麼它不起作用。您可能需要在多種情況下分開提取，例如當len（row）== 5'做一次轉換，並且當'len（row）== 6'做其他轉換時 – PerunSS

但是如果我寫IF ELSe條件它的拋出錯誤@PerunSS – venkat

你可以添加你試過的？ – PerunSS

下面是答案，

import csv 
import json 

with open('output.txt', 'r') as csvfile: # Opens file 
    filereader = csv.reader(csvfile, delimiter=' ') 
    i = 0 
    header = [] 
    out_data = [] 
    for row in filereader: 
     row = [elem for elem in row if elem] 
     if i == 0: 
      i+=1 
      row[1:3] = [row[1]+" "+row[2]] # Design Project key 
      row[2:4] = [row[2]+" "+row[3]] # Design Target key 
      row[3:5] = [row[3]+" "+row[4]] # Median Property* 
      header = row 

     elif len(row) == 8: 

      row[0:4] = [row[0]+" "+row[1]+" "+row[2]+" "+row[3]] # Metric value 

      if row[1] == 'Not': 
       row[1:3] = [row[1]+" "+row[2]] 
      else: 
       row[1:2] = [row[1]] # Design Project Value 
       row[2:4] = [row[2]+" "+row[3]] # Design Target 

      _dict = {} 
      for elem, header_elem in zip(row, header): 
       _dict[header_elem] = elem 
      out_data.append(_dict) 

     elif len(row) == 7: 
      #print len(row) 
      row[0:3]=[row[0]+" "+row[1]+" "+row[2]] # Metric Value 
      row[1:2] = [row[1]] # Design Project value 
      row[2:4] = [row[2]+" "+row[3]] # Design Target 

      _dict = {} 
      for elem, header_elem in zip(row, header): 
       _dict[header_elem] = elem 
      out_data.append(_dict) 

     else: 
      row[0:6] = [row[0]+" "+row[1]+" "+row[2]+" "+row[3]+" "+row[4]+" "+row[5]] # Metric Value 
      row[1:2] = [row[1]] # Design Project value 
      row[2:4] = [row[2]+" "+row[3]] # Design Target 
      _dict = {} 
      for elem, header_elem in zip(row, header): 
       _dict[header_elem] = elem 
      out_data.append(_dict) 

    print json.dumps(out_data)

來源

2017-10-21 13:02:14 venkat

將文本數據轉換爲Json格式

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