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我看過了幾個SO職位,以及在其他網站上的文章,並且還沒有找到一個有效的答案:(警告:mysql_fetch_assoc():提供的參數不是一個有效的MySQL結果資源
這裏是我的代碼:
include("db_conn.php");
$conn = mysql_connect($db_host, $db_user, $db_pass) or die(mysql_error()); mysql_select_db($db_name) or die(mysql_error());
$timestamp = time();
$add_time = time()+(60*60);
$query = "SELECT * FROM links WHERE timestamp >= '$timestamp' AND overflow = 'NO'";
$result = mysql_query($query);
if(mysql_num_rows($result) > 0) {
while($row = mysql_fetch_assoc($result)){
$link = $row['link'];
$hit_update = rand($row['min'],$row['max']);
$query = "UPDATE links SET timestamp = '$add_time', hit_counter = '0', max_hits = '$hit_update' WHERE link = '$link' AND timestamp <= '$timestamp' AND overflow = 'NO'";
$result = mysql_query($query) or die(mysql_error());
}
}
mysql_close($conn);
它會返回錯誤:
Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource
要診斷我已經試過:
- 拆卸裝箱
if()
聲明。 - 註釋掉
while()
循環,並在$result = mysql_query($query);
下面添加$size = mysql_num_rows($result); echo $size;
,它返回3
,即查詢本身沒有任何問題。
有誰知道這個問題可能是什麼?
任何答案將非常感謝!
問題在於更新 您重寫$ result變量 – galchen