mysql complex joins

Question

這與mysql query with AND, OR and NOT還有mysql has all values我已經解決了AND部分問題，但是現在我現在還需要解決OR和NOT。

只是爲了確認下面的語句給我，讓每個題目1，2和3

SELECT x.* 
FROM Article x INNER JOIN 
(SELECT t.article_id, COUNT(t.article_id) 
    FROM articleTopics t 
    WHERE t.topic_id IN ('1','2','3') 
    GROUP BY t.article_id 
    HAVING COUNT(t.article_id)>=3 
    ORDER BY COUNT(t.article_id) DESC 
    LIMIT 0,100) AS ilv 
ON x.id=ilv.article_id 

我所試圖做的就是添加的東西會排除也是所有文章查詢所有文章與主題4和5相關聯：NOT

我還希望添加包含主題6或7的文章，只要它們符合先前的約束。

E.g.

SELECT all Articles where the articles has 
    all the following topics (1,2,3) #AND 
AND 
    none of the following topics (4,5) #NOT 
AND 
    may have any of the following topics(6,7) #OR 

我希望有道理！

Answer 1

這是我結束了：

SELECT x.* 
FROM Article x INNER JOIN 
(SELECT t.article_id, COUNT(t.article_id) 
    FROM articleTopics t 
    WHERE t.topic_id IN ('1','2','3') 
    AND NOT EXISTS (
     SELECT 1 
     FROM articleTopics 
     WHERE article_id = t.article_id 
     AND entity_id IN ('4','5')) 
    GROUP BY t.article_id 
    HAVING COUNT(t.article_id)>=3 
    ORDER BY COUNT(t.article_id) DESC 
    LIMIT 0,100) AS ilv 
ON x.id=ilv.article_id 
LEFT JOIN articleTopics at ON at.article_id = x.id 
WHERE ae_topic_id IN ('6','7') 

這是說所有的文章必須包含所有主題1,2,3和ATLEAST 1 6或7但從不包括4或5

感謝您的幫助。

Answer 2

我會用EXISTS功能，如：

SELECT ... 
FROM Article a 
WHERE EXISTS (SELECT topic_id FROM articleTopics t WHERE t.article_id = a.article_id AND topic_id = 1) 
    AND EXISTS (SELECT topic_id FROM articleTopics t WHERE t.article_id = a.article_id AND topic_id = 2) 
    AND EXISTS (SELECT topic_id FROM articleTopics t WHERE t.article_id = a.article_id AND topic_id = 3) 
    AND NOT EXISTS (SELECT topic_id FROM articleTopics t WHERE t.article_id = a.article_id AND topic_id = 4) 
    AND NOT EXISTS (SELECT topic_id FROM articleTopics t WHERE t.article_id = a.article_id AND topic_id = 5) 
    AND (EXISTS (SELECT topic_id FROM articleTopics t WHERE t.article_id = a.article_id AND topic_id = 6) 
    OR EXISTS (SELECT topic_id FROM articleTopics t WHERE t.article_id = a.article_id AND topic_id = 7)) 

Answer 3

好像這將是更易於使用常規JOIN比使用子查詢。應該也更快。

SELECT * FROM articles JOIN articleTopics USING(article_id) 
WHERE topic_id IN(1,2,3) AND topic_id NOT IN (4,5) GROUP BY article_id; 

我不明白爲什麼你需要指定6和7.除非你說它是否有6或7，其他規則並不重要。在這種情況下，你可以這樣做：

SELECT * FROM articles JOIN articleTopics USING(article_id) 
    WHERE (topic_id IN(1,2,3) AND topic_id NOT IN (4,5)) OR topic_id IN(6,7) GROUP BY article_id;