我試圖讓我的代碼塊非線程安全,以便玩弄一些我希望稍後添加的異常。這個python代碼是線程安全的嗎?
這是我的Python代碼:
from time import sleep
from decimal import *
from threading import Lock
import random
def inc_gen(c):
"""
Increment generator
"""
while True:
#getting sleep period
timing_rand = random.randrange(0,1000)
print "INC: Sleeping for " + str(Decimal(timing_rand)/Decimal(1000))
sleep(Decimal(timing_rand)/Decimal(1000))
c.inc()
yield c
def dec_gen(c):
"""
decrement generator
"""
while True:
#getting sleep period
timing_rand = random.randrange(0,1000)
print "DEC: Sleeping for " + str(Decimal(timing_rand)/Decimal(1000))
sleep(Decimal(timing_rand)/Decimal(1000))
c.dec()
yield c
class something():
"""
We use an obj instead of an atomic variable c, we can have "threads"
simulating shared resources, instead of a single variable, to avoid
atomic instructions. (which is thread-safe in python thanks to GIL)
"""
def __init__(self):
self.c = 0
def inc(self):
self.c += 1
def dec(self):
self.c -= 1
def value(self):
return self.c
def main():
"""
main() function
"""
obj = something()
counters = [inc_gen(obj),dec_gen(obj)]
#we only want inc_gen 10 times, and dec_gen 10 times.
inc = 0 #number of times inc_gen is added
dec = 0 #number of times dec_gen is added
while True:
#choosing the next counter
if inc < 10 and dec < 10:
counter_rand = random.randrange(0,2)
if counter_rand == 0:
inc += 1
else: dec += 1
elif inc < 10 and dec == 10:
inc += 1
counter_rand = 0
elif dec < 10 and inc == 10:
dec += 1
counter_rand = 1
else: break
counters[counter_rand].next()
#print for testing
print "Final value of c: " + str(obj.value())
if __name__ == "__main__":
main()
有代碼可能導致其不爲0
它是線程安全的最終值我希望它做的是什麼?如果不是,我該如何使它不是線程安全的?
呃,你剛纔問過這個(http://stackoverflow.com/questions/1717393),並且得到了答案。你爲什麼用示例代碼問完全相同的問題,這些代碼在邏輯上相同但不必要更復雜? – 2009-11-12 09:13:10