我試圖創建一個登錄的用戶更新的功能,但我得到這樣的錯誤:PHP - mysql_result()預計參數1是資源,布爾給
「mysql_result()預計參數1是資源,布爾給出「
有人可以幫我找出問題嗎?
$pagee_query = mysql_query("SELECT COUNT(*) FROM order");
$pages = ceil(mysql_result($pagee_query, 0)/$per_pagee);
$pagee = (isset($_GET['pagee'])) ? (int)$_GET['pagee'] : 1;
$start = ($pagee - 1) * $per_pagee;
$query = mysql_query("SELECT * FROM `order` LIMIT $start, $per_pagee");
while ($data = mysql_fetch_array($query)) {
?>
<tr>
<td><?php echo $data['order_id']; ?></td>
<td><?php echo $data['id']; ?></td>
<td><?php echo $data['name']; ?></td>
<td><?php echo $data['address']; ?></td>
<td><?php echo $data['code']; ?></td>
<td><?php echo $data['name_nl']; ?></td>
<td><a href="delete-pesan.php?id=<?php echo $data['order_id'];?>"class="btn" onclick="return confirm('Are you Sure ?')")><i class="icon-trash"></i></a></td>
</tr>
<?php
}
?>
。
<?php
if($pages >= 1 && $pagee <= $pages)
{
for($x=1; $x<=$pages; $x++)
{
if($x == $pagee)
echo ' <b><a href="?pagee='.$x.'">'.$x.'</a></b> | ';
else
echo ' <a href="?pagee='.$x.'">'.$x.'</a> |';
}
}
?>
謝謝..它工作得很好.. – awang
不客氣 – DASH