合併不同大小的列表。裝滿最小

Question

我在想，如果是，執行以下任一模塊：

A = [ A, B, C ] 
B = [ 24 ] 

C = [ (24, A), (24, B) , (24, C) ] 

感謝

Answer 1

>>> A = ['A', 'B', 'C'] 
>>> B = [24] 

>>> import itertools 
>>> list(zip(itertools.cycle(B), A)) 
[(24, 'A'), (24, 'B'), (24, 'C')] 

---

如果您B是['24']，不[24]，嘗試：

>>> A = ['A', 'B', 'C'] 
>>> B = ['24'] 

>>> import itertools 
>>> list(zip(itertools.cycle(map(int, B)), A)) 
[(24, 'A'), (24, 'B'), (24, 'C')] 

我想你知道嗎？ int對象和STR對象之間fference ...

Answer 2

無需任何外部模塊要求，這將在具體情況下工作：

A = ['A', 'B', 'C'] 
B = [24] 
C = zip(B * len(A), A) 
print C 

[(24, 'A'), (24, 'B'), (24, 'C')]