Eclipse Tomcat錯誤404

我是一名試圖學習JSF的新手。你能幫我在日食中的錯誤404 ..！我試圖通過進入屬性更改服務器的詳細信息，但它仍然給我錯誤。Eclipse Tomcat錯誤404

請幫我這個。提前致謝。

我登錄的代碼是folows：

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> 
<html xmlns="http://www.w3.org/1999/xhtml" 
     xmlns:ui="http://java.sun.com/jsf/facelets" 
     xmlns:h="http://java.sun.com/jsf/html" 
     xmlns:f="http://java.sun.com/jsf/core"> 

    <head><title>JSF Login</title></head> 
<body> 
    <h1>Login</h1> 
<h:form> 
<table> 
<tr> 
<td><h:outputText value="Username: " /></td> 
<td><h:inputText id="loginname" 
value="#{loginBean.uname}" /> 
</td> 
</tr> 
<tr> 
<td><h:outputText value="Password: " /></td> 
<td><h:inputSecret id="password" 
value="#{loginBean.password}" /> 
</td> 
</tr> 
<tr> 
<td> </td> 
<td><h:commandButton value="Login" 
action="#{loginBean.loginProject()}"/> 
</td> 
</tr> 

</h:form> 
</body> 
</html>

我loginbean文件：

package beans; 

import dao.UserDAO; 
import java.io.Serializable; 
import javax.faces.application.FacesMessage; 
import javax.faces.bean.ManagedBean; 
import javax.faces.bean.SessionScoped; 
import javax.faces.context.FacesContext; 
import javax.servlet.http.HttpSession; 

@ManagedBean(name = "loginBean") 
@SessionScoped 
/** 
* 
* @author User 
*/ 
public class LoginBean implements Serializable { 

    private static final long serialVersionUID = 1L; 
    private String password; 
    private String message, uname; 

    public String getMessage() { 
     return message; 
    } 

    public void setMessage(String message) { 
     this.message = message; 
    } 

    public String getPassword() { 
     return password; 
    } 

    public void setPassword(String password) { 
     this.password = password; 
    } 

    public String getUname() { 
     return uname; 
    } 

    public void setUname(String uname) { 
     this.uname = uname; 
    } 

    public String loginProject() { 
     boolean result = UserDAO.login(uname, password); 
     if (result) { 
      // get Http Session and store username 
      HttpSession session = Util.getSession(); 
      session.setAttribute("username", uname); 

      return "home"; 
     } else { 

      FacesContext.getCurrentInstance().addMessage(
        null, 
        new FacesMessage(FacesMessage.SEVERITY_WARN, 
        "Invalid Login!", 
        "Please Try Again!")); 

      // invalidate session, and redirect to other pages 

      //message = "Invalid Login. Please Try Again!"; 
      return "login"; 
     } 
    } 

    public String logout() { 
     HttpSession session = Util.getSession(); 
     session.invalidate(); 
     return "login"; 
    } 
}

web.xml文件：

<?xml version="1.0" encoding="UTF-8"?> 
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd" id="WebApp_ID" version="3.1"> 
<context-param> 
    <param-name>javax.faces.PROJECT_STAGE</param-name> 
    <param-value>Development</param-value> 
</context-param> 
    <listener> 
     <listener-class> 
      com.sun.faces.config.ConfigureListener 
     </listener-class> 
    </listener> 
<welcome-file-list> 
    <welcome-file>login.xhtml</welcome-file> 
</welcome-file-list> 

</web-app>

來源

2014-09-03 Pranay Tare

假設所有的依賴性在那裏，其他所有配置您只需將以下內容添加到您的web.xml中即可。我還建議你閱讀java ee 7教程，並使用Netbeans，因爲你剛剛開始。

<servlet> 
    <servlet-name>Faces Servlet</servlet-name> 
    <servlet-class>javax.faces.webapp.FacesServlet</servlet-class> 
    <load-on-startup>1</load-on-startup> 
    </servlet> 
    <servlet-mapping> 
    <servlet-name>Faces Servlet</servlet-name> 
    <url-pattern>*.xthml</url-pattern> 
    </servlet-mapping>

來源

2014-09-03 13:17:29 zulq

謝謝，爲答覆..這對我有效。 – 2014-09-05 10:05:42

歡迎您，很高興它的工作。 – zulq 2014-09-05 10:55:51

Eclipse Tomcat錯誤404

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