Bash Linux Curl從變量發送頭文件

Question

我在bash中有一些腳本。 我想發送一個請求到服務器與一些頭（cloudflare塊:)。

我寫了這個：

headers="\ 
-H 'Host: somesite.com' \ 
-H 'Accept-Language: pl,en-US;q=0.7,en;q=0.3' \ 
-H 'Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8' \ 
-H 'User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64; rv:32.0) Gecko/20100101 Firefox/32.0' \ 
-H 'Accept-Encoding: gzip, deflate' \ 
-H 'DNT: 1' \ 
-H 'Connection: keep-alive'"; 

curl $headers somesite.com 

但在輸出我有這個..

curl: (6) Couldn't resolve host 'Accept-Language' 
curl: (6) Couldn't resolve host 'pl,en-US;q=0.7,en;q=0.3' 
curl: (6) Couldn't resolve host 'Accept' 
curl: (6) Couldn't resolve host 'text' 
curl: (6) Couldn't resolve host 'User-Agent' 
curl: (6) Couldn't resolve host 'Mozilla' 
curl: (6) Couldn't resolve host '(Windows' 
curl: (6) Couldn't resolve host 'NT' 
curl: (6) Couldn't resolve host '6.1;' 

我怎樣才能把標題從變量插入命令？

Answer 1

請勿爲此使用字符串。試圖在像這樣的字符串中正確引用是不可能的，請使用數組。

有關更多信息，請參閱http://mywiki.wooledge.org/BashFAQ/050。