我正面臨一個問題。誰能幫我 首先,我有兩個型號如何在laravel中的多個關聯表中調用5.2
1)user.php的
enter code here
public function listings(){
return $this->hasOne('App\Listing','user_id')
->with("topservices");
}
現在我有上市型號
2)(Listing.php)
enter code here
public function topservices(){
return $this->hasMany('App\Sellerprofile','list_id');
}
現在我有一個功能
enter code here
public function nails(){
$users = DB::table('users')
->where(['service_name'=>"Seller"])
->get();
$users = json_decode(json_encode($users),true);
foreach($users as $alluser){
$ids[] = $alluser['id'];
}
if(!empty($ids)){
$allData = User::with('listings')->whereIn('id',$ids)->get();
$allData = json_decode(json_encode($allData),true);
echo "<pre>"; print_r($allData); die; ///when i print this array it gives me below output
}
$title = "Nails";
return view("listings.listing",['allData'=>$allData,'title'=>$title]);
}
輸出:
enter code here
Array
(
[0] => Array
(
[id] => 1
[title] => Mr
[firstname] => kunal
[email] => [email protected]
[listings] => Array
(
[id] => 1
[user_id] => 1
[type] => premimum
[business_name] => kunal
[topservices] => Array
(
[0] => Array
(
[id] => 5
[service_id] => 1
[list_id] => 1
[name] => Acrylic
[duration] => 10mins
[price] => 10
)
[1] => Array
(
[id] => 6
[service_id] => 2
[list_id] => 1
[name] => Hair Top
[duration] => 30mins
[price] => 20
)
[2] => Array
(
[id] => 7
[service_id] => 3
[list_id] => 1
[name] => Skin Care Top
[duration] => 1hr-30mins
[price] => 30
)
[3] => Array
(
[id] => 8
[service_id] => 4
[list_id] => 1
[name] => Massage Top
[duration] => 20mins
[price] => 50
)
)
)
)
[1] => Array
(
[id] => 2
[title] => Mr
[firstname] => kunal
[email] => [email protected]
[listings] => Array
(
[id] => 2
[user_id] => 2
[type] => premimum
[topservices] => Array
(
[0] => Array
(
[id] => 9
[service_id] => 6
[list_id] => 2
[name] => Acrylic
[duration] => 30mins
[price] => 10
)
[1] => Array
(
[id] => 10
[service_id] => 6
[list_id] => 2
[name] => Powder gel nails
[duration] => 45mins
[price] => 20
)
[2] => Array
(
[id] => 11
[service_id] => 6
[list_id] => 2
[name] => Polish change
[duration] => 10mins
[price] => 25
)
[3] => Array
(
[id] => 12
[service_id] => 6
[list_id] => 2
[name] => Hand design
[duration] => 2hrs
[price] => 100
)
[4] => Array
(
[id] => 13
[service_id] => 7
[list_id] => 2
[name] => Hair Top
[duration] => 30mins
[price] => 200
)
)
)
)
)
現在你上面的輸出看到有Topservices陣列我想下topservices其價格大於等於比= 10,少到30 我的預期成果是所有這些陣列: -
enter code here
Array
(
[0] => Array
(
[id] => 1
[title] => Mr
[firstname] => kunal
[email] => [email protected]
[listings] => Array
(
[id] => 1
[user_id] => 1
[type] => premimum
[business_name] => kunal
[topservices] => Array
(
[0] => Array
(
[id] => 5
[service_id] => 1
[list_id] => 1
[name] => Acrylic
[duration] => 10mins
[price] => 10
)
[1] => Array
(
[id] => 6
[service_id] => 2
[list_id] => 1
[name] => Hair Top
[duration] => 30mins
[price] => 20
)
)
)
)
[1] => Array
(
[id] => 2
[title] => Mr
[firstname] => kunal
[email] => [email protected]
[listings] => Array
(
[id] => 2
[user_id] => 2
[type] => premimum
[topservices] => Array
(
[0] => Array
(
[id] => 9
[service_id] => 6
[list_id] => 2
[name] => Acrylic
[duration] => 30mins
[price] => 10
)
[1] => Array
(
[id] => 10
[service_id] => 6
[list_id] => 2
[name] => Powder gel nails
[duration] => 45mins
[price] => 20
)
[2] => Array
(
[id] => 11
[service_id] => 6
[list_id] => 2
[name] => Polish change
[duration] => 10mins
[price] => 25
)
)
)
)
)
任何人都可以幫助我。在此先感謝我所做的指甲功能
不工作@jaysingkar它給我的錯誤(爆炸()預計參數2爲字符串,對象給出):( – kunal
使用價格whereBetween價格列不在列表表格是在topservices希望你能理解它給了我錯誤(在'where子句'中的未知列'價格'(SQL:select * from'listing',其中'(1,2)'中的列表'''用戶標識'和10到30之間的'價格')) – kunal