Sql獲得員工每週工作時間每週的開始日期（例如星期，星期一，星期二等的開始日期）

Question

我有這張表，用於保存用戶登錄註銷詳細信息。 我想查詢數據與周開始一天，並每週獲取數據， 例如，如果我從2016年3月1日查詢到2016年3月28日，我的開始一週是週三，那麼我需要每週所有員工數據 3月2日至8日 3月9日至15日 3月16日至22日 爲每名員工。如果有人在那個星期工作了40多個小時，那麼我還需要額外計算一小時。

CREATE TABLE #tempWeekdatbefore 
(EmployeeId BIGINT, LoginTime DATETIME, LogOutTime DATETIME) 


INSERT INTO #tempWeekdatbefore (EmployeeId,LoginTime,LogOutTime) 
Values 
(83  ,'2016-03-09 06:55:22.000', '2016-03-09 14:29:11.000'), 
(98  ,'2016-03-09 07:04:22.000', '2016-03-09 11:53:12.000'), 
(84  ,'2016-03-09 07:07:06.000', '2016-03-09 13:39:03.000'), 
(136 ,'2016-03-09 07:29:14.000', '2016-03-09 13:20:24.000'), 
(420 ,'2016-03-09 07:33:48.000', '2016-03-09 11:42:52.000'), 
(101102 ,'2016-03-09 07:49:25.000', '2016-03-09 11:42:53.000'), 
(425 ,'2016-03-09 07:49:45.000', '2016-03-09 12:47:46.000'), 
(100750 ,'2016-03-09 07:56:26.000', '2016-03-09 12:43:16.000'), 
(90  ,'2016-03-09 08:03:51.000', '2016-03-09 11:19:38.000'), 
(78  ,'2016-03-09 08:52:09.000', '2016-03-09 13:26:56.000'), 
(89  ,'2016-03-09 09:06:57.000', '2016-03-09 13:41:30.000'), 
(60600 ,'2016-03-09 09:31:17.000', '2016-03-09 17:13:48.000'), 
(219 ,'2016-03-09 11:50:51.000', '2016-03-09 15:07:42.000'), 
(90  ,'2016-03-09 11:54:38.000', '2016-03-09 16:47:30.000'), 
(420 ,'2016-03-09 12:12:33.000', '2016-03-09 14:53:59.000'), 
(101102 ,'2016-03-09 12:12:42.000', '2016-03-09 16:43:33.000'), 
(337 ,'2016-03-09 12:17:22.000', '2016-03-09 15:54:39.000'), 
(98  ,'2016-03-09 12:22:27.000', '2016-03-09 16:39:59.000'), 
(425 ,'2016-03-09 13:08:09.000', '2016-03-09 17:00:16.000'), 
(100750 ,'2016-03-09 13:09:32.000', '2016-03-09 15:00:00.000'), 
(136 ,'2016-03-09 13:32:12.000', '2016-03-09 16:00:00.000'), 
(84  ,'2016-03-09 13:50:37.000', '2016-03-09 16:23:04.000'), 
(89  ,'2016-03-09 14:11:00.000', '2016-03-09 15:00:00.000'), 
(101147 ,'2016-03-09 14:52:07.000', '2016-03-09 19:03:44.000'), 
(81  ,'2016-03-09 14:54:05.000', '2016-03-09 19:08:47.000'), 
(219 ,'2016-03-09 15:31:52.000', '2016-03-09 19:08:48.000'), 
(100701 ,'2016-03-09 16:00:18.000', '2016-03-09 19:05:08.000'), 
(337 ,'2016-03-09 16:27:44.000', '2016-03-09 19:08:50.000'), 
(90  ,'2016-03-09 16:54:34.000', '2016-03-09 17:38:00.000') 

SELECT EmployeeId 
,SUM(CASE WHEN ISNULL(RegTime, 0)>40 THEN RegTime-40 ELSE 0 END) AS ExtraHour 
,SUM(CASE WHEN ISNULL(RegTime, 0)>40 THEN 40 ELSE RegTime END) AS RegTime 
FROM(

Select EmployeeId, 
    DATEPART(dw,LoginTime) AS WeekNumber, 
    DATEPART(MONTH,LoginTime) AS MonthNumber, 
    DATEPART(Year,LoginTime) AS YearNumber, 
    SUM(CONVERT(decimal(18, 2), 
    DATEDIFF(MINUTE, LoginTime, isnull(LogOutTime,getdate()))/60.00)) AS RegTime 
FROM  #tempWeekdatbefore WITH(NOLOCK) 
WHERE  (convert(date, LoginTime) >= convert(date, '3/9/2016')) AND 
(convert(date,LogOutTime) <= convert(date, '3/9/2016')) 
GROUP BY EmployeeId, DATEPART(dw,LoginTime), 
DATEPART(MONTH,LoginTime), DATEPART(Year,LoginTime)) as e 
GROUP BY EmployeeId, WeekNumber, MonthNumber, YearNumber 

Answer 1

我做了全面建設的BusinessObjects宇宙（First day of previous week with a twist）時確定先前，當前和下一週的第一天，最後天，一週中的變量開始的第一天一些工作。

顯然，與BusinessObjects部分不適用，但我仍然認爲潛在的SQL可能仍然會有所幫助......

declare @StartDate datetime 
declare @StartDateDayOfWeek int 
declare @BeginningDayOfWeek int 

set @StartDate = '03/01/2016' 
set @StartDateDayOfWeek = DATEPART(dw, @StartDate) 

set @BeginningDayOfWeek = 4 --Wednesday 

select DATEADD(DAY, (-7 + ((@StartDateDayOfWeek - @BeginningDayOfWeek + 7) % 7)) * -1, @StartDate) 
, DATEADD(DAY, (-13 + ((@StartDateDayOfWeek - @BeginningDayOfWeek + 7) % 7)) * -1, @StartDate) 
, DATEADD(DAY, (-14 + ((@StartDateDayOfWeek - @BeginningDayOfWeek + 7) % 7)) * -1, @StartDate) 
, DATEADD(DAY, (-20 + ((@StartDateDayOfWeek - @BeginningDayOfWeek + 7) % 7)) * -1, @StartDate) 
, DATEADD(DAY, (-21 + ((@StartDateDayOfWeek - @BeginningDayOfWeek + 7) % 7)) * -1, @StartDate) 
, DATEADD(DAY, (-27 + ((@StartDateDayOfWeek - @BeginningDayOfWeek + 7) % 7)) * -1, @StartDate) 

如果複製SQL和運行它，你會得到你所提到的日期。你顯然需要適應你的情況，但希望這會讓你朝着正確的方向前進。

Noel