從一個頁面發送隱變量到另一個

Question

我有一個登錄腳本，它在我的主頁我的登錄表單，這也是在我的主頁。當用戶提交表單登錄時，他/她提交他/她的用戶名和密碼。

腳本訪問數據庫具有用戶名，密碼和電子郵件來自注冊用戶存儲的地址。

一旦用戶登錄成功，他/她將被重定向到其在同一數據庫中存儲不同的表內的網頁上加載他們以前的「評論」頁面。

我需要從一個表發送電子郵件到查詢重定向的頁面上。

這裏是我的PHP代碼，處理登錄的代碼：

<?php 

//If the user has submitted the form 
if(isset($_REQUEST['username'])){ 
    //protect the posted value then store them to variables 
    $username = protect($_POST['username']); 
    $password = protect($_POST['password']); 

    //Check if the username or password boxes were not filled in 
    if(!$username || !$password){ 
     //if not display an error message 
     echo "<center>You need to fill in a <b>Username</b> and a <b>Password</b>!</center>"; 
    }else{ 
     //if they were continue checking 

     //select all rows from the table where the username matches the one entered by the user 
     $res = mysql_query("SELECT * FROM `users` WHERE `username` = '".$username."'"); 
     $num = mysql_num_rows($res); 

     //check if there was no match 
     if($num == 0){ 
      //if none, display an error message 
      echo "<center>The <b>Username</b> you supplied does not exist!</center>"; 
     }else{ 
      //if there was a match continue checking 

      //select all rows where the username and password match the ones submitted by the user 
      $res = mysql_query("SELECT * FROM `users` WHERE `username` = '".$username."' AND `password` = '".$password."'"); 
      $num = mysql_num_rows($res); 

      //check if there was no match 
      if($num == 0){ 
       //if none display error message 
       echo "<center>The <b>Password</b> you supplied does not match the one for that username!</center>"; 
      }else{ 
       //if there was continue checking 

       //split all fields from the correct row into an associative array 
       $row = mysql_fetch_assoc($res); 

       //check to see if the user has not activated their account yet 
       if($row['active'] != 1){ 
        //if not display error message 
        echo "<center>You have not yet <b>Activated</b> your account!</center>"; 
       }else{ 
        //if they have log them in 

        //set the login session storing there id - we use this to see if they are logged in or not 
        $_SESSION['uid'] = $row['id']; 


        //update the online field to 50 seconds into the future 
        $time = date('U')+50; 
        mysql_query("UPDATE `users` SET `online` = '".$time."' WHERE `id` = '".$_SESSION['uid']."'"); 

        //redirect them to the usersonline page 
        echo 'REDIRECT'; 

       } 
      } 
     } 
    } 

    exit; 
} 

?> 

這裏是PHP代碼，就重新定向到頁面：

<?php 
    $con=mysqli_connect("","","",""); 
    // Check connection 
    if (mysqli_connect_errno()) 
    { 
    echo "Failed to connect to MySQL: " . mysqli_connect_error(); 
    } 
    $result = mysqli_query($con,"SELECT * FROM comments 
    WHERE email='$_POST[email]' ORDER BY dt"); 

    while($row = mysqli_fetch_array($result)) 
    { 
    echo $row['dt'] ." " . $row['email'] . " " . $row['body']; 
    echo "<br>"; 
    echo "<br>"; 
    } 
?> 

我需要添加第一個代碼從表格中提取電子郵件地址，以驗證登錄信息並將其發送到第二個代碼以接收「評論」。我試着用Google搜索一個答案，並沒有提出任何建議。請幫忙！

Answer 1

既然你已經使用在代碼中$_SESSION陣列（這可能是從什麼地方複製），您可以將電子郵件地址類似存儲在同一陣列英寸

$_SESSION['email'] = $row['email']; 

---

在後來的頁面，你需要用$_SESSION['email']更換$_POST['email']。