2017-08-28 71 views
2

在SQL Server Management Studio中,有一個「生成併發布腳本嚮導」上下文菜單選項,可以自動爲表數據生成插入語句腳本。如何使用SQL Server中的命令行自動生成腳本?

在我的情況下,我只能訪問使用命令行的數據庫查詢。含義我無法訪問「生成和發佈腳本嚮導」。

使用純SQL或T-SQL命令行可以實現類似的功能嗎?

+3

一個選項是Powershell,如果你有權訪問它。 [使用Powershell和SMO自動生成腳本 - Phil因子](https://www.red-gate.com/simple-talk/sql/database-administration/automated-script-generation-with-powershell-and-smo/ ) – SqlZim

+0

這是一個很好的寫什麼是和不可能的https://dba.stackexchange.com/questions/95262/get-object-script-in-sql-server-via-t-sql –

回答

0

這是一個基本的SQL構建基於系統視圖插入:

DECLARE @sqlinsert AS VARCHAR(MAX) = '' 
DECLARE @tbl AS VARCHAR(128)='dbo.mytable' 

SET @sqlinsert = 'DECLARE 
' 

SELECT @sqlinsert = @sqlinsert + ' 
@ins_' + c.name + ' ' + t.name 
+ IIF(t.max_length>=8000,'('+ CONVERT(VARCHAR(16),c.max_length) +')','')+ ','--c.column_id, c.name,c.system_type_id,t.name,c.max_length,t.max_length,c.* 
FROM sys.tables a 
JOIN sys.schemas b ON a.schema_id = b.schema_id 
JOIN sys.columns c ON c.object_id = a.object_id 
JOIN sys.types t ON t.system_type_id = c.system_type_id AND t.system_type_id <> 231 
WHERE b.name+'.'+a.name = @tbl 
AND is_rowguidcol = 0 AND is_identity = 0 AND is_computed = 0 
ORDER BY c.column_id 

SET @sqlinsert = SUBSTRING(@sqlinsert,1,LEN(@sqlinsert)-1) 

SET @sqlinsert = @sqlinsert + ' 
Insert Into ' + @tbl + ' (' 

SELECT @sqlinsert = @sqlinsert + ' 
[' + c.name + '],'--c.column_id, c.name,c.system_type_id,t.name,c.max_length,t.max_length,c.* 
FROM sys.tables a 
JOIN sys.schemas b ON a.schema_id = b.schema_id 
JOIN sys.columns c ON c.object_id = a.object_id 
JOIN sys.types t ON t.system_type_id = c.system_type_id AND t.system_type_id <> 231 
WHERE b.name+'.'+a.name = @tbl 
AND is_rowguidcol = 0 AND is_identity = 0 AND is_computed = 0 
ORDER BY c.column_id 

SET @sqlinsert = SUBSTRING(@sqlinsert,1,LEN(@sqlinsert)-1) 
SET @sqlinsert = @sqlinsert + ') 
Values (' 

SELECT @sqlinsert = @sqlinsert + ' 
@ins_' + c.name + ','--c.column_id, c.name,c.system_type_id,t.name,c.max_length,t.max_length,c.* 
FROM sys.tables a 
JOIN sys.schemas b ON a.schema_id = b.schema_id 
JOIN sys.columns c ON c.object_id = a.object_id 
JOIN sys.types t ON t.system_type_id = c.system_type_id AND t.system_type_id <> 231 
WHERE b.name+'.'+a.name = @tbl 
AND is_rowguidcol = 0 AND is_identity = 0 AND is_computed = 0 
ORDER BY c.column_id 

SET @sqlinsert = SUBSTRING(@sqlinsert,1,LEN(@sqlinsert)-1) 
SET @sqlinsert = @sqlinsert + ')' 

SELECT @sqlinsert 

--SELECT * FROM sys.types 

也許你可能需要一些更多的過濾器/如果你的表沒有覆蓋的專業閱讀SYS意見的情況。

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