如何使用boto將文件上傳到S3存儲桶中的目錄

Question

我想使用python複製s3存儲桶中的文件。

例如：我有桶名稱=測試。並在桶中，我有2個文件夾名稱「轉儲」&「輸入」。現在我想複製一個文件從本地目錄到S3「轉儲」文件夾使用python ...任何人都可以幫助我嗎？

Answer 1

嘗試......

import boto 
import boto.s3 
import sys 
from boto.s3.key import Key 

AWS_ACCESS_KEY_ID = '' 
AWS_SECRET_ACCESS_KEY = '' 

bucket_name = AWS_ACCESS_KEY_ID.lower() + '-dump' 
conn = boto.connect_s3(AWS_ACCESS_KEY_ID, 
     AWS_SECRET_ACCESS_KEY) 


bucket = conn.create_bucket(bucket_name, 
    location=boto.s3.connection.Location.DEFAULT) 

testfile = "replace this with an actual filename" 
print 'Uploading %s to Amazon S3 bucket %s' % \ 
    (testfile, bucket_name) 

def percent_cb(complete, total): 
    sys.stdout.write('.') 
    sys.stdout.flush() 


k = Key(bucket) 
k.key = 'my test file' 
k.set_contents_from_filename(testfile, 
    cb=percent_cb, num_cb=10) 

[更新] 我不是pythonist，所以感謝擡起頭對import語句。另外，我不建議在你自己的源代碼中放置證書。如果您正在運行這裏面AWS使用與實例概要文件IAM憑證（http://docs.aws.amazon.com/IAM/latest/UserGuide/id_roles_use_switch-role-ec2_instance-profiles.html），並保持相同的行爲在你的開發/測試環境中，使用這樣的全息圖將AdRoll（https://github.com/AdRoll/hologram）

Answer 2

我用這個，這是非常簡單地實現

import tinys3 

conn = tinys3.Connection('S3_ACCESS_KEY','S3_SECRET_KEY',tls=True) 

f = open('some_file.zip','rb') 
conn.upload('some_file.zip',f,'my_bucket') 

https://www.smore.com/labs/tinys3/

Answer 3

沒有必要弄得這麼複雜：

s3_connection = boto.connect_s3() 
bucket = s3_connection.get_bucket('your bucket name') 
key = boto.s3.key.Key(bucket, 'some_file.zip') 
with open('some_file.zip') as f: 
    key.send_file(f) 

Answer 4

from boto3.s3.transfer import S3Transfer 
import boto3 
#have all the variables populated which are required below 
client = boto3.client('s3', aws_access_key_id=access_key,aws_secret_access_key=secret_key) 
transfer = S3Transfer(client) 
transfer.upload_file(filepath, bucket_name, folder_name+"/"+filename) 

Answer 5

這也將工作：

import os 
import boto 
import boto.s3.connection 
from boto.s3.key import Key 

try: 

    conn = boto.s3.connect_to_region('us-east-1', 
    aws_access_key_id = 'AWS-Access-Key', 
    aws_secret_access_key = 'AWS-Secrete-Key', 
    # host = 's3-website-us-east-1.amazonaws.com', 
    # is_secure=True,    # uncomment if you are not using ssl 
    calling_format = boto.s3.connection.OrdinaryCallingFormat(), 
    ) 

    bucket = conn.get_bucket('YourBucketName') 
    key_name = 'FileToUpload' 
    path = 'images/holiday' #Directory Under which file should get upload 
    full_key_name = os.path.join(path, key_name) 
    k = bucket.new_key(full_key_name) 
    k.set_contents_from_filename(key_name) 

except Exception,e: 
    print str(e) 
    print "error" 

Answer 6

import boto 
from boto.s3.key import Key 

AWS_ACCESS_KEY_ID = '' 
AWS_SECRET_ACCESS_KEY = '' 
END_POINT = ''       # eg. us-east-1 
S3_HOST = ''       # eg. s3.us-east-1.amazonaws.com 
BUCKET_NAME = 'test'   
FILENAME = 'upload.txt'     
UPLOADED_FILENAME = 'dumps/upload.txt' 
# include folders in file path. If it doesn't exist, it will be created 

s3 = boto.s3.connect_to_region(END_POINT, 
          aws_access_key_id=AWS_ACCESS_KEY_ID, 
          aws_secret_access_key=AWS_SECRET_ACCESS_KEY, 
          host=S3_HOST) 

bucket = s3.get_bucket(BUCKET_NAME) 
k = Key(bucket) 
k.key = UPLOADED_FILENAME 
k.set_contents_from_filename(FILENAME) 

Answer 7

import boto3 

s3 = boto3.resource('s3') 
BUCKET = "test" 

s3.Bucket(BUCKET).upload_file("your/local/file", "dump/file")