2011-09-30 84 views
3

我試圖建立在目前的RSS閱讀器我使用的 例如從任何RSS提要獲取飼料標題用PHP

$xml->item->title 

PHP的SimpleXML但是但是這取決於結構如果結構不同,rss會提供自己的信息,但它不會工作,所以我想知道是否有更廣泛和更不具體的方式來抓取RSS提要中的所有標題。

非常感謝

回答

1

你可以使用一些正則表達式來過濾RSS文件,並將它們分成無論你想要什麼標題等。正如您將定義要從中獲取數據的標籤。

使用類似:$regex = '/<(w+)[^>]*>(.*?)</\1>/s'; preg_match_all($reg_exp, $text, $match);

+0

嘿,我已經使用過一次正則表達式,但我似乎只能針對標記的第一次出現,無論如何要循環遍歷文件中的所有標題標記? – <span class="text-secondary"> <small> <a rel="noopener" target="_blank" href="https://stackoverflow.com/users/827570/">user827570</a></span> <span></span> </small> </span> </p> </div> </div> </div> <div itemprop="comment" class="post-comment"> <div class="row"> <div class="col-lg-1"><span class="text-secondary">+0</span></div> <div class="col-lg-11"> <p class="commenttext">是的,的確,您可以使用「preg_match_all()」函數而不是「preg_match()」。然後使用「foreach」循環遍歷結果。 – <span class="text-secondary"> <small> <a rel="noopener" target="_blank" href="https://stackoverflow.com/users/408777/">Mido</a></span> <span></span> </small> </span> </p> </div> </div> </div> <div itemprop="comment" class="post-comment"> <div class="row"> <div class="col-lg-1"><span class="text-secondary">+0</span></div> <div class="col-lg-11"> <p class="commenttext">爲什麼在有XML解析器出現的時候使用RegEx來做到這一點......解析XML文件。 – <span class="text-secondary"> <small> <span></span> </small> </span> </p> </div> </div> </div> </div> </div> </article> <div> <script async src="//pagead2.googlesyndication.com/pagead/js/adsbygoogle.js"></script> <ins class="adsbygoogle" style="display:block" data-ad-client="ca-pub-6208739752673518" data-ad-slot="4319274062" data-ad-format="auto" data-full-width-responsive="true"></ins> <script> (adsbygoogle = window.adsbygoogle || []).push({}); </script> </div> <article class="board-top-1 padding-top-10"> <div class="post-col vote-info"> <span class="count">3<i class="fa fa-thumbs-up"></i></span> </div> <div class="post-offset"> <div class="answer fmt"> <p>也許it's再次使用這樣的貢獻,而不是發明輪子一個選擇:<a href="http://www.phpclasses.org/package/3724-PHP-Parse-and-display-items-of-an-RSS-feed.html" rel="nofollow">http://www.phpclasses.org/package/3724-PHP-Parse-and-display-items-of-an-RSS-feed.html</a></p> </div> <div class="post-info"> <div class="post-meta row"> <p class="text-secondary col-lg-6"> <span class="source"> <a rel="noopener" target="_blank" href="https://stackoverflow.com/q/7606552">來源</a> </span> </p> <p class="text-secondary col-lg-6"> <span class="float-right date"> <span>2011-09-30 06:11:22</span> <a rel="noopener" target="_blank" href="https://stackoverflow.com/users/909365/">0xDEADBEEF</a></span> </p> <p class="col-12"></p> <p class="col-12"></p></div> </div> <!-- comments --> <div class="comments"> <div itemprop="comment" class="post-comment"> <div class="row"> <div class="col-lg-1"><span class="text-secondary">+1</span></div> <div class="col-lg-11"> <p class="commenttext">我不會那麼用,但是(例如)Zend Framework帶有一個不錯的RSS類。 – <span class="text-secondary"> <small> <span></span> </small> </span> </p> </div> </div> </div> </div> </div> </article> <article class="board-top-1 padding-top-10"> <div class="post-col vote-info"> <span class="count">4<i class="fa fa-thumbs-up"></i></span> </div> <div class="post-offset"> <div class="answer fmt"> <p>有一個RSS文件規範那裏。你可以在<a href="http://cyber.law.harvard.edu/rss/rss.html" rel="nofollow">http://cyber.law.harvard.edu/rss/rss.html</a></p> <p>因此,一個RSS文件總是看起來一樣,但要小心。總是有像Atom這樣的東西。</p> <p>您可以使用XPath的RSS中搜索:<a href="http://nl.php.net/manual/en/simplexmlelement.xpath.php" rel="nofollow">http://nl.php.net/manual/en/simplexmlelement.xpath.php</a></p> </div> <div class="post-info"> <div class="post-meta row"> <p class="text-secondary col-lg-6"> <span class="source"> <a rel="noopener" target="_blank" href="https://stackoverflow.com/q/7606565">來源</a> </span> </p> <p class="text-secondary col-lg-6"> <span class="float-right date"> <span>2011-09-30 06:12:23</span> </p> <p class="col-12"></p> <p class="col-12"></p></div> </div> </div> </article> <article class="board-top-1 padding-top-10"> <div class="post-col vote-info"> <span class="count">1<i class="fa fa-thumbs-up"></i></span> </div> <div class="post-offset"> <div class="answer fmt"> <p>有很多的飼料格式。編寫代碼以符合所有,是一項有點困難的任務。所以..</p> <p>我推薦使用簡單的派。 <a href="http://simplepie.org/" rel="nofollow">http://simplepie.org/</a> 或者您也可以使用<a href="http://code.google.com/apis/feed/v1/jsondevguide.html" rel="nofollow">google feed api</a>。這裏是一個使用簡單派的例子。 <a href="http://simplepie.org/wiki/setup/sample_page" rel="nofollow">http://simplepie.org/wiki/setup/sample_page</a></p> </div> <div class="post-info"> <div class="post-meta row"> <p class="text-secondary col-lg-6"> <span class="source"> <a rel="noopener" target="_blank" href="https://stackoverflow.com/q/7606631">來源</a> </span> </p> <p class="text-secondary col-lg-6"> <span class="float-right date"> <span>2011-09-30 06:21:12</span> <a rel="noopener" target="_blank" href="https://stackoverflow.com/users/522050/">pahan</a></span> </p> <p class="col-12"></p> <p class="col-12"></p></div> </div> </div> </article> <div> <script async src="//pagead2.googlesyndication.com/pagead/js/adsbygoogle.js"></script> <ins class="adsbygoogle" style="display:block" data-ad-client="ca-pub-6208739752673518" data-ad-slot="4319274062" data-ad-format="auto" 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