{
"data": [
{
"business_type": "bar",
"business_name": "KKK",
"number": "1234567",
"business_id": "test1"
},
{
"business_type": "restauratns",
"business_name": "KKKK",
"number": "1234567",
"business_id": "test2"
}
]
}
PHP代碼: -解析JSON在PHP不工作
1)是否加工
foreach ($json_array->data as $obj) {
echo $obj->business_name;
echo $obj->business_type;
echo $obj->business_id;
}
2)僅得到輸出的 「數據陣」,但沒有獲得對象的詳細信息
foreach ($json_array as $name=>$value) {
echo "$name: $value\n";
foreach ($value as $entry) {
echo ' ' . $entry->business_type;
echo ' ' . $entry->business_name;
echo ' ' . $entry->business_id;
echo ' ' . $entry->number;
}
}
之後我也試着用print_r和var_dump來打印細節。
結果的var_dump是: -
array(1) {
["data"]=>
array(2) {
[0]=>
array(4) {
["business_type"]=>
string(3) "bar"
["business_name"]=>
string(3) "KKK"
["number"]=>
string(7) "1234567"
["business_id"]=>
string(5) "test1"
}
[1]=>
array(4) {
["business_type"]=>
string(11) "restauratns"
["business_name"]=>
string(4) "KKKK"
["number"]=>
string(7) "1234567"
["business_id"]=>
string(5) "test2"
}
}
}
我想找到我在哪裏犯錯,但沒有得到任何想法。如果有人有任何想法,請引導我。