DATE重複，直到while循環讀取記錄

Question

請檢查圖像，它將解釋視覺

http://dubads.com/temp/Untitled-1.jpg

for ($index = 1; $index <= $numdays; $index++) { 

    $users = 
     "SELECT invoice_date, DAY(invoice_date) as invoiceday, " . 
     "sum(total_amount) as fullamount from invoices " . 
     "WHERE MONTH(invoice_date)='".$month."' AND YEAR(invoice_date)='".$year. 
     "' GROUP BY invoiceday"; 
    $res = mysql_query($users); 
    $row = mysql_num_rows($res); 

    while ($fetch = mysql_fetch_array($res)) { 

     echo "<tr id='".(($j % 2 == 0) ? 'row3' : 'row4')."'>"; 

     $explodedate = explode("-", $fetch['invoice_date']); 
     $days = $explodedate[2]; 
     $month1 = $explodedate[1]; 
     $year1 = $explodedate[0]; 

     $dates = date("jS", strtotime($fetch['invoice_date'])); 

     echo "<td style='text-align:left;padding-left:12px'>".$index. 
      "</td>"; 
     if ($index == $dates) { 

      echo "<td style='text-align:right;padding-right:12px'>". 
       $fetch['fullamount']."</td>"; 

     } else { 

      echo "<td style='text-align:right;padding-right:12px'>--</td>"; 

     } 

     echo "</tr>"; 
    } 
} 

$total = 
    "SELECT SUM(total_amount) as fulltotal from invoices where MONTH(invoice_date)='". 
    $month1."' AND YEAR(invoice_date)='".$year1."';"; 

$totres = mysql_query($total); 
$totfetch = mysql_fetch_assoc($totres); 
if ($totfetch['fulltotal'] == "") { 
    echo "<tr><td>NOTHING FOUND</td></tr>"; 
} else { 
    ECHO "<TR>"; 
    echo "<td style='color:#BD0000;padding-left:12px;border:1px solid #ccc;width:20%;height:40px;text-align:left'>TOTAL AMOUNT </td>"; 
    echo "<td style='color:#BD0000;border:1px solid #ccc;width:20%;height:40px;text-align:right;padding-right:12px'>".$totfetch['fulltotal']."</TD></TR>"; 

} 

echo "</table>"; 

Answer 1

你已經得到一個循環計數$指數。我會電子書籍，使指數爲基礎的0，但是這不是你的問題：

你已經得到了外循環：

for ($index = 1; $index <= $numdays; $index++) { 
    ... 
} 

它

和你有內環，至極是做輸出每條記錄：

while ($fetch = mysql_fetch_array($res)) { 
    ... 
} 

因此，您每天輸出查詢返回的所有記錄。

我不能給你任何建議，如何解決這個問題，因爲我看不到，你想做什麼。也許你可以解釋，哪些記錄可以顯示，何時！

哦，你的html語法出錯了！一個ID必須是唯一的。在你的情況下，你應該使用class not id！

編輯：

啊...好吧，我想我可以想像，你的意思！

你想每天和你想還一個空行空天一行...

其實相當容易，我開始寫它......可能需要大約5分鐘！

編輯二：

for ($index = 0; $index < $numdays; $index++) 
{ 

    $sql = 
     'SELECT sum(total_amount) as fullamount from invoices ' . 
     'WHERE MONTH(invoice_date)=\'' . $month . '\' AND YEAR(invoice_date)=\'' . $year . 
     '\' And DAY(invoice_date)=\'' . ($index+1) . '\';'; 

    $res = mysql_query($sql); 
    $row = mysql_fetch_array($res)) 

    echo '<tr class=\'' . (($j % 2 == 0) ? 'row3' : 'row4') . '\'>' . "\n"; 
    echo '<td style=\'text-align:left;padding-left:12px\'>' . ($index+1) . '</td>' . "\n"; 

    if($row['fullamount']!=null&&$row['fullamount']!=''&&$row['fullamount']!=0) 
    { 
     echo '<td style=\'text-align:right;padding-right:12px\'>' . $row['fullamount'] . '</td>' . "\n"; 
    } 
    else 
    { 
     echo '<td style=\'text-align:right;padding-right:12px\'>--</td>' . "\n"; 
    } 

    echo '</tr>' . "\n"; 
} 

$sql = 
    'SELECT SUM(total_amount) as fulltotal from invoices where MONTH(invoice_date)=\'' . 
    $month . '\' AND YEAR(invoice_date)=\'' . $year . '\';'; 

$res = mysql_query($sqö); 
$fetch = mysql_fetch_array($res); 

if ($fetch['fulltotal'] == '') 
{ 
    echo '<tr><td>NOTHING FOUND</td></tr>'; 
} 
else 
{ 
    echo '<tr>' . "\n"; 
    echo '<td style=\'color:#BD0000;padding-left:12px;border:1px solid #ccc;width:20%;height:40px;text-align:left\'>TOTAL AMOUNT </td>' . "\n"; 
    echo '<td style=\'color:#BD0000;border:1px solid #ccc;width:20%;height:40px;text-align:right;padding-right:12px\'>' . $fetch['fulltotal'] . '</td>'; 
    echo '</tr>' . "\n"; 
} 

echo '</table>'; 

我希望，這可以幫助你！祝你好運！