swift3 uitableView重載使屏幕閃爍

Question

我使用UITableview，它看起來與Instagram的feed類似。這個問題我有

1. 我有一個類似的功能在每個tableviewCell
2. 當像按鈕點擊，它需要更新屏幕，屏幕閃爍
3. 在tableview中cellForRowAt功能，我有一個網絡調用檢查類似的號碼。

請讓我知道是否有辦法避免這種眨眼。我應該避免使用此功能進行網絡通話還是有其他方法？

U可以看到我下面的一些代碼部分：

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell { 
    let cell = tableView.dequeueReusableCell(withIdentifier: "Cell", for: indexPath) as! StoryReviewTableViewCell 

    let review = ReviewArray[indexPath.row] 

    // 프로필 이미지랑 닉네임 설정 
    if let user = review.creator { 
     let nickname = user.getProperty("nickname") as! String 
     cell.profileName.text = nickname 

     if let profileURL = user.getProperty("profileURL") { 
      if profileURL is NSNull { 
       cell.profileImage.image = #imageLiteral(resourceName: "user_profile") 
      } else { 
       let url = URL(string: profileURL as! String) 
       DispatchQueue.main.async { 
        cell.profileImage.kf.setImage(with: url, placeholder: #imageLiteral(resourceName: "imageLoadingHolder"), options: [.transition(.fade(0.2))], progressBlock: nil, completionHandler: nil) 
       } 
      } 
     } 
    } else { 
     // 삭제된 유저의 경우 
     cell.profileName.text = "탈퇴 유저" 
     cell.profileImage.image = #imageLiteral(resourceName: "user_profile") 
    } 

    // 장소 이름 
    if let store = ReviewArray[indexPath.row].store { 
     cell.storeName.text = "장소: \(String(describing: store.name!))" 
    } else { 
     cell.storeName.text = "가게 이름" 
    } 


    // 라이크버튼 설정 - 라이크 모양은 여기서 컨트롤, delegate에서 user 라이크 컨트롤 
    DispatchQueue.global(qos: .userInteractive).async { 

     let likeStore = Backendless.sharedInstance().data.of(ReviewLikes.ofClass()) 
     let dataQuery = BackendlessDataQuery() 

     let objectID = review.objectId! 
     let userID = UserManager.currentUser()!.objectId! 
     // print("objectID & userID: \(objectID) & \(userID)") 

     // 여기서 by가 현재 유저의 objectId이어야 하고, to는 이 리뷰의 objectId이어야 한다 
     dataQuery.whereClause = "by = '\(userID)' AND to = '\(objectID)'" 

     DispatchQueue.main.async { 
      likeStore?.find(dataQuery, response: { (collection) in 
       let likes = collection?.data as! [ReviewLikes] 

       // 하트를 안 눌렀을 때 
       if likes.count == 0 { 
        DispatchQueue.main.async { 
         cell.likeButton.setImage(#imageLiteral(resourceName: "like_bw"), for: .normal) 
        } 
       } else { 
        DispatchQueue.main.async { 
         cell.likeButton.setImage(#imageLiteral(resourceName: "like_red"), for: .normal) 
        } 
       } 

      }, error: { (Fault) in 
       print("라이크 불러오기에서 에러: \(String(describing: Fault?.description))") 
      }) 

     } 

     // 좋아요 개수 세기 
     let countQuery = BackendlessDataQuery() 
     // to가 story의 objectID와 일치하면 땡 
     countQuery.whereClause = "to = '\(objectID)'" 

     let queryOptions = QueryOptions() 
     queryOptions.pageSize = 1 
     countQuery.queryOptions = queryOptions 

     DispatchQueue.global(qos: .userInteractive).async { 
      let matchingLikes = likeStore?.find(countQuery) 
      let likeNumbers = matchingLikes?.totalObjects 

      DispatchQueue.main.async { 
       if likeNumbers == 0 { 
        cell.likeLabel.text = "라이크 없음 ㅠ" 
       } else { 
        cell.likeLabel.text = "\(String(describing: likeNumbers!))개의 좋아요" 
       } 
      } 
     } 
    } 

    // 리뷰 평점 배당 
    cell.ratingView.value = review.rating as! CGFloat 

    // 리뷰 바디 
    cell.reviewBody.text = review.text 

    // 코멘트 개수 받아오기 
    DispatchQueue.global(qos: .userInteractive).async { 
     // 댓글수 찾기 
     let tempStore = Backendless.sharedInstance().data.of(ReviewComment.ofClass()) 

     let reviewId = review.objectId! 
     let dataQuery = BackendlessDataQuery() 
     // 이 리뷰에 달린 댓글 모두 몇 개인지 찾기 
     dataQuery.whereClause = "to = '\(reviewId)'" 

     DispatchQueue.main.async { 
      tempStore?.find(dataQuery, response: { (collection) in 
       let comments = collection?.data as! [ReviewComment] 

       cell.replyLabel.text = "댓글 \(comments.count)개" 

      }, error: { (Fault) in 
       print("서버에서 댓글 얻어오기 실패: \(String(describing: Fault?.description))") 
      }) 
     } 
    } 

    cell.timeLabel.text = dateFormatter.string(from: review.created! as Date) 

    return cell 
} 

U可以看到這裏的按鈕操作

@IBAction func likeButtonClicked(_ sender: UIButton) { 

    likeButton.isUserInteractionEnabled = false 

    // delegate action 
    delegate?.actionTapped(tag: likeButton.tag) 

    // image change 
    if sender.image(for: .normal) == #imageLiteral(resourceName: "like_bw") { 
     UIView.transition(with: sender, duration: 0.2, options: .transitionCrossDissolve, animations: { 
      sender.setImage(#imageLiteral(resourceName: "like_red"), for: .normal) 
     }, completion: nil) 
     self.likeButton.isUserInteractionEnabled = true 
    } else { 
     UIView.transition(with: sender, duration: 0.2, options: .transitionCrossDissolve, animations: { 
      sender.setImage(#imageLiteral(resourceName: "like_bw"), for: .normal) 
     }, completion: nil) 
     self.likeButton.isUserInteractionEnabled = true 
    } 
} 

這是隻有重裝該行我的委託函數的一部分

func changeLike(_ row: Int, _ alreadyLike: Bool, completionHandler: @escaping (_ success:Bool) -> Void) { 

    let selectedReview = ReviewArray[row] 
    let reviewId = selectedReview.objectId 

    // 그냥 유저 객체로 비교는 안되고 objectId로 체크를 해야 함 
    let objectID = Backendless.sharedInstance().userService.currentUser.objectId 

    let dataStore = Backendless.sharedInstance().data.of(ReviewLikes.ofClass()) 

    // 좋아요 - alreadyLike가 true이면 
    if !alreadyLike { 
     // 객체 생성 

     let like = ReviewLikes() 
     like.by = objectID! as String 
     like.to = reviewId 

     dataStore?.save(like, response: { (response) in 

      DispatchQueue.main.async { 

       let indexPath = IndexPath(row: row, section: 0) 
       self.tableView.reloadRows(at: [indexPath], with: .none) 

      } 
    } 

Answer 1

let cell = self.tblView.cellForRow(at: IndexPath(row: index, section: 0)) as! UITableViewCell 
cell.btnLike.setImage(UIImage(named: (isReviewed! ? IMG_LIKE : IMG_UNLIKE)), for: .normal) 

J ust更新單元格，而不是在tableview中重新加載整個數據。

Answer 2

嘗試調用上按一下按鈕，而不是數據的cellForRowAtIndexPath並使用該按鈕，點擊重新加載數據，而不是

@IBAction func likeButtonClicked(_ sender: UIButton) { 
    let buttonPosition:CGPoint = sender.convert(CGPointZero, to:self.tableView) 

    let indexPath = self.tableView.indexPathForRow(at: buttonPosition) 
    let cell = tableView.cellForRow(at: indexPath) as! StoryReviewTableViewCell 

      DispatchQueue.main.async { 
         likeStore?.find(dataQuery, response: { (collection) in 
          let likes = collection?.data as! [ReviewLikes] 

          // 하트를 안 눌렀을 때 
          if likes.count == 0 { 
           DispatchQueue.main.async { 
            cell.likeButton.setImage(#imageLiteral(resourceName: "like_bw"), for: .normal) 
           } 
          } else { 
           DispatchQueue.main.async { 
            cell.likeButton.setImage(#imageLiteral(resourceName: "like_red"), for: .normal) 
           } 
          } 

         }, error: { (Fault) in 
          print("라이크 불러오기에서 에러: \(String(describing: Fault?.description))") 
         }) 



      }