如何使用XmlPullParser解析複雜的XML

Question

嗨，大家好我有XML解析的問題。我試圖用XmlPullParser

XML看起來像解析：

<lfm status="ok"> 
    <topartists user="dailz" type="overall" page="1" perPage="50" totalPages="30" total="1493"> 
     <artist rank="1"> 
      <name>Oasis</name> 
      <url>http://www.last.fm/music/Oasis</url> 
      <image size="small">http://userserve-ak.last.fm/serve/34/44937531.jpg</image> 
      <image size="large">http://userserve-ak.last.fm/serve/126/44937531.jpg</image> 
     </artist> 
     <artist rank="2"> 
      ... 
     </artist> 
    </topartists> 
</lfm> 

這就是我想要做的事：

public class TopArtistsParser { 

    private static final String ns = null; 
    private static final String TAG = "TopArtistsParser"; 

    public class Artist { 

     public final String rank; 
     public final String name; 
     public final String url; 
     public final String image; 

     private Artist(String rank, String name, String url, String image) { 
      this.rank = rank; 
      this.name = name; 
      this.url = url; 
      this.image = image; 
     } 

    } 

    public List<Artist> parse(InputStream in) throws XmlPullParserException, 
      IOException { 
     MyLog.d(TAG, "List<Artist> parse"); 
     try { 
      XmlPullParser parser = Xml.newPullParser(); 
      parser.setFeature(XmlPullParser.FEATURE_PROCESS_NAMESPACES, false); 
      parser.setInput(in, null); 
      parser.nextTag(); 
      return readFeed(parser); 
     } finally { 
      in.close(); 
     } 
    } 

    private List<Artist> readFeed(XmlPullParser parser) 
      throws XmlPullParserException, IOException { 

     MyLog.d(TAG, "List<Artist> readFeed"); 
     List<Artist> artistsList = new ArrayList<Artist>(); 

     parser.require(XmlPullParser.START_TAG, ns, "lfm"); 
     while (parser.next() != XmlPullParser.END_TAG) { 
      if (parser.getEventType() != XmlPullParser.START_TAG) { 
       continue; 
      } 
      String tag = parser.getName(); 
      if (tag.equals("artist")) { 
       MyLog.d(TAG, "tag == 'artist'"); 
       artistsList.add(readArtist(parser)); 
      } else { 
       skip(parser); 
      } 
     } 

     return artistsList; 
    } 

    private Artist readArtist(XmlPullParser parser) 
      throws XmlPullParserException, IOException { 

     MyLog.d(TAG, "Artist readArtist"); 
     parser.require(XmlPullParser.START_TAG, ns, "artist"); 

     String rank = null; 
     String name = null; 
     String url = null; 
     String image = null; 

     while (parser.next() != XmlPullParser.END_TAG) { 
      if (parser.getEventType() != XmlPullParser.START_TAG) { 
       continue; 
      } 
      String tag = parser.getName(); 
      if (tag.equals("name")) { 
       name = readName(parser); 
       MyLog.d(TAG, "tag == 'name': " + name); 
      } else if (tag.equals("url")) { 
       url = readUrl(parser); 
       MyLog.d(TAG, "tag == 'url': " + url); 
      } else if (tag.equals("image")) { 
       image = readImage(parser); 
       MyLog.d(TAG, "tag == 'image': " + image); 
      } else { 
       skip(parser); 
      } 
     } 

     return new Artist(rank, name, url, image); 
    } 

    private String readName(XmlPullParser parser) throws IOException, 
      XmlPullParserException { 
     MyLog.d(TAG, "readName"); 
     parser.require(XmlPullParser.START_TAG, ns, "name"); 
     String name = readText(parser); 
     parser.require(XmlPullParser.END_TAG, ns, "name"); 
     return name; 
    } 

    private String readUrl(XmlPullParser parser) throws IOException, 
      XmlPullParserException { 
     MyLog.d(TAG, "readUrl"); 
     parser.require(XmlPullParser.START_TAG, ns, "url"); 
     String url = readText(parser); 
     parser.require(XmlPullParser.END_TAG, ns, "url"); 
     return url; 
    } 

    private String readImage(XmlPullParser parser) throws IOException, 
      XmlPullParserException { 
     MyLog.d(TAG, "readImage"); 
     parser.require(XmlPullParser.START_TAG, ns, "image"); 
     String image = readText(parser); 
     parser.require(XmlPullParser.END_TAG, ns, "image"); 
     return image; 
    } 

    private String readText(XmlPullParser parser) throws IOException, 
      XmlPullParserException { 
     MyLog.d(TAG, "readText"); 
     String result = ""; 
     if (parser.next() == XmlPullParser.TEXT) { 
      result = parser.getText(); 
      parser.nextTag(); 
     } 
     return result; 
    } 

    private void skip(XmlPullParser parser) throws XmlPullParserException, 
      IOException { 

     MyLog.d(TAG, "skip"); 

     if (parser.getEventType() != XmlPullParser.START_TAG) { 
      throw new IllegalStateException(); 
     } 
     int depth = 1; 
     while (depth != 0) { 
      switch (parser.next()) { 
      case XmlPullParser.END_TAG: 
       depth--; 
       break; 
      case XmlPullParser.START_TAG: 
       depth++; 
       break; 
      } 
     } 
    } 
} 

我看着Parsing XML Data，但它並沒有幫助我。

你能幫我解析一下嗎：等級，名稱，網址，圖片（大小很大）？

Answer 1

我這個廣告代碼和所有工作

<!-- language: java --> 

while (parser.next() != XmlPullParser.END_TAG) { 
     if (parser.getEventType() != XmlPullParser.START_TAG) { 
      continue; 
     } 
     String tag = parser.getName(); 
     if (tag.equals("topartists")) { 
      MyLog.d(TAG, "tag == " + tag); 
      tag = parser.getName(); 

     } else if (tag.equals("artist")) { 
      MyLog.d(TAG, "tag == " + tag); 
      artistsList.add(readArtist(parser)); 
     } else { 
      skip(parser); 
     } 
    } 

Answer 2

我會建議SimpleXML給你解析更復雜的XML數據，或只使用XPath