我想執行一個PHP腳本,以發送電子郵件。我已在的cPanel的cronjob到文件,但通路時,發送的電子郵件我收到Cronjob PHP腳本輸出不執行需要腳本
X供電-者:PHP/43年5月4日 內容類型:text/html的
在在的cronjob的cPanel我已經把下面的代碼:
php /home/themesby/public_html/reminder/trimite-email.php
,我要執行的代碼如下:
<?php
include('db-connect.php');
$number_of_days_before = 1;
$email = "[email protected]";
$reminder_details = "";
$todays_date = date("Ymd");
$year = substr($todays_date, 0, 4);
$month = substr($todays_date, 4, 2);
$date = substr($todays_date, 6, 2);
$trigger_date = date("Ymd", mktime (0,0,0,$month,$date-$number_of_days_before,$year));
$result = mysql_query("SELECT * FROM evenimente WHERE data_eveniment <=$trigger_date ORDER BY data_eveniment ASC");
$nr = mysql_num_rows($result);
while($row = mysql_fetch_array($result))
{
$year = substr($row["data_eveniment"], 0, 4);
$month = substr($row["data_eveniment"], 4, 2);
$date = substr($row["data_eveniment"], 6, 2);
$data_eveniment = date("M j, Y", mktime (0,0,0,$month,$date,$year));
$reminder_details .= "Eveniment: ".$row["nume_eveniment"]."\n";
$reminder_details .= "Data: ".$data_eveniment."\n";
$reminder_details .= $row["descriere_eveniment"]."\n\n";
}
mysql_free_result($result);
if(!empty($nr))
{
$mailheader = "From: Planificator <$email>\nX-Mailer: Reamintire\nContent-Type: text/plain";
mail("$email","Reamintire","$reminder_details","$mailheader");
// Delete the sent reminders
mysql_query("DELETE FROM evenimente WHERE data_eveniment <= $trigger_date");
}
?>
什麼可能是問題的根源? Thx提前。
注意:'mysql_ *'功能已被棄用,他們已經從PHP 7刪除,你的代碼將停止工作,當你升級到那個版本。您不應使用它們編寫新代碼,而應使用['mysqli_ *'或PDO](http://php.net/manual/en/mysqlinfo.api.choosing.php)。 –
你的腳本處於危險之中,你應該避免使用mysql_ – ameenulla0007
當你直接調用它而沒有crond的時候腳本是否工作? –